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So my code looks like this

#include <stdio.h>

void print_line(int index, int cents, int value)
{
printf("print_line(%d, %d, %d)\n", index, cents, value);
}
void coins(int cents)
{
    printf("coins(%d)\n", cents);
}
int main(void)
{
    int dollars, cents;
    printf("Pls enter total val");
    int n = scanf("%d.%d, &dollars, ¢s");
    if (n! = 2)
    {
        printf("Did not type correct\n");
    }
    else if (dollars < 0)
    {
        printf("dollars specified must be non neg\n");
    }
    else if (cents < 0 || cents > 99)
    {
        printf("The cents part spec mjust be 0...99");
    }
    else
    {
        coins(1+1);
    }
return 0;


    printf("main()\n");
}


I'm aware it has problems, I'm just trying to troubleshoot errors. For this line

int n = scanf("%d.%d, &dollars, ¢s");


the error comes up format ‘%d’ expects a matching ‘int *’ argument. And for this line

if (n! = 2)


The error is "error: expected ‘)’ before ‘!’ token"

How do I fix these

What I have tried:

I tried altering my code alr, but most of my alterations just cause more errors.
Posted
Updated 1-Oct-21 7:25am

1 solution

int n = scanf("%d.%d, &dollars, ¢s");
// the ¢s here has no meaning and the senond double quote is in the wrong place
I'm guessing you want something like,

int n = scanf("%d.%d", &dollars, &cents);


and
if (n! = 2)

should be
if (n != 2) // the '!' and '=' should be next to each other to be the inequality operator 
 
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