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Telephone Company has the following rate structure for long distance calls:
a. any call started after 7 PM (1900 hours) but before 8:00 AM (0800 hours) is deducted 40%.
b. any call started after 8:00 AM (0800 hours) but before 7 PM (1900 hours) is charged full.
c. all calls are subjected to 6% tax.
d. the regular rate for a call is Php 7.00 per minute.
e. Any can longer than 60 minutes receives a 17% discount on its cost (after any other discount is subtracted but before tax is added).

Make a program that takes the start time for a call based on a 24 hour clock and the duration of the call in minutes. The gross cost (before any discount or tax) should be displayed followed by the net cost (after discount is deducted and tax added).

What I have tried:

#include<stdio.h>


int main()
{
    int time,min;
    float priceperminute=7, discount=0, grosscost=0, netcost=0;
    
    printf("START TIME:");
    scanf("%d", &time);
    printf("DURATION:");
    scanf("%d", &min);
    
    grosscost=min*priceperminute;
    
    if(time<=800 && time>=1900)
    if(time<=1900&&time>=800)
    {
        netcost=grosscost;
 }
    else
    netcost=grosscost*0.17;
    
    if (min<=60)
    netcost-= netcost*0.40;


    float tax= netcost*6/100;
    netcost-netcost+tax;


    printf("Grosscost:%.2f",grosscost);
    printf("\nNetcost:%.2f", netcost);
    return 0;    

}
Posted
Updated 23-Feb-22 23:06pm

Compiling does not mean your code is right! :laugh:
Think of the development process as writing an email: compiling successfully means that you wrote the email in the right language - English, rather than German for example - not that the email contained the message you wanted to send.

So now you enter the second stage of development (in reality it's the fourth or fifth, but you'll come to the earlier stages later): Testing and Debugging.

Start by looking at what it does do, and how that differs from what you wanted. This is important, because it give you information as to why it's doing it. For example, if a program is intended to let the user enter a number and it doubles it and prints the answer, then if the input / output was like this:
Input   Expected output    Actual output
  1            2                 1
  2            4                 4
  3            6                 9
  4            8                16
Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:
C
int Double(int value)
   {
   return value * value;
   }

Once you have an idea what might be going wrong, start using the debugger to find out why. Put a breakpoint on the first line of the method, and run your app. When it reaches the breakpoint, the debugger will stop, and hand control over to you. You can now run your code line-by-line (called "single stepping") and look at (or even change) variable contents as necessary (heck, you can even change the code and try again if you need to).
Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
Hopefully, that should help you locate which part of that code has a problem, and what the problem is.
This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!
 
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C++
if(time<=800 && time>=1900)
if(time<=1900&&time>=800)

The time cannot be less or equal to 800 and greater than or equal to 1900 at the same time. It must be either the first OR the second. And placing two such if statements together will never work.
 
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