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I am trying to get multiple input but i cant get. In The first line of input it should contain an integer 'T' representing the number of test cases or queries to be processed.

The first line of each test case contains two single space-separated integers ‘N’ and ‘K’ representing the size of the vector/list and the given integer, respectively.

The second line of each test case contains ‘N’ single space-separated integers representing the vector elements.

For example like this,

2(T total integers)

2 3 (n and k)
1 3 (array)

3 2 (n and k)
1 -2 1 (array)

It should get

as output.

But i am getting only 12
Why the code doesnt run more?

explanation of code:

2 3 (arr should be 2 *3 times)
So [ 1 , 3 , 1 , 3, 1, 3]
Maximum sum is 12
Can anyone help me to solve this problem

What I have tried:

for i in range(n*k):
    currsum = currsum + arr[i%n]
    if currsum > maxsum:
        maxsum = currsum
    if currsum < 0:
        currsum =0
Updated 3-Mar-22 1:52am
Richard MacCutchan 3-Mar-22 6:20am    
You need to repeat the code for T iterations. In your sample you ignore the value of T.
sanjay surya 3-Mar-22 6:41am    
if i ignore the value of t, the code is running a error
Richard MacCutchan 3-Mar-22 6:52am    
See below.

Getting it to run at all does not mean your code is right! :laugh:
Think of the development process as writing an email: compiling successfully means that you wrote the email in the right language - English, rather than German for example - not that the email contained the message you wanted to send.

So now you enter the second stage of development (in reality it's the fourth or fifth, but you'll come to the earlier stages later): Testing and Debugging.

Start by looking at what it does do, and how that differs from what you wanted. This is important, because it give you information as to why it's doing it. For example, if a program is intended to let the user enter a number and it doubles it and prints the answer, then if the input / output was like this:
Input   Expected output    Actual output
  1            2                 1
  2            4                 4
  3            6                 9
  4            8                16
Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:
int Double(int value)
   return value * value;

Once you have an idea what might be going wrong, start using the debugger to find out why. Put a breakpoint on the first line of the method, and run your app. When it reaches the breakpoint, the debugger will stop, and hand control over to you. You can now run your code line-by-line (called "single stepping") and look at (or even change) variable contents as necessary (heck, you can even change the code and try again if you need to).
Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
Hopefully, that should help you locate which part of that code has a problem, and what the problem is.

If you don't know how to use a debugger, start here: pdb — The Python Debugger — Python 3.10.2 documentation[^]

This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!
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This is what you need to do:
t = int(input())
while t > 0:
    # get the next test case details
    # do the calculation(s)
    # print the result(s)
    t = t - 1 # decrement the loop control
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