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Write a function named `freq(l)` that takes a list `l` of numbers
and returns a tuple of the most frequent number and its frequency.
For example, `freq([1,2,3,4,5,2,3,4,5,3,4,5,4,5,4]) returns (4,5)
because number 4 appears 5 times in this list. If multiple numbers
appear as most frequent, then the first element of the returned
tuple is a list of all those numbers. For example,

freq([1,2,3,1,2,1,2,3,1,2]) will return ([1,2], 4) because both
1 and 2 appear 4 times in the list.


How can i solve this in Python.

What I have tried:

I do'not not have idea regarding this..
Posted
Updated 23-Mar-22 5:38am

Not exactly what you need, but close to.
Python
def freq(l):
  s = { x for x in l } # a set: get the unique values 
  lt = [ (x, l.count(x)) for x in s ] # list of tuple containing unique values and their occurrences in the list
  mv = max(lt,key=lambda item:item[1])[1] # the maximum number of occurrences
  r = ([ x for (x,v) in lt if v == mv], mv) # the resulting tuple, filtering out all the items with less occurrences than the maximum
  return r
   
Quote:
I do'not not have idea regarding this..

The first idea is "How do I solve it by hand ?"
Then "Can I apply the 'by hand' solution to programming ?"
In short, you can't just have no idea.

In case you really have no idea for such a simple thing, you need to talk with your teacher.
   

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