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Hi guys. I'm kinda new into MySQL and PHP. but im in this challenge and im slowly getting things done.

I was about to test the website and I get this error:
Fatal error: Uncaught TypeError: mysqli_connect(): Argument #1 ($hostname) must be of type ?string, array given in C:\xampp\htdocs\scandiweb-test-assignment\connect.php:8 Stack trace: #0 C:\xampp\htdocs\scandiweb-test-assignment\connect.php(8): mysqli_connect(Array, Array, Array, Array) #1 C:\xampp\htdocs\scandiweb-test-assignment\index.php(3): include('C:\\xampp\\htdocs...') #2 {main} thrown in C:\xampp\htdocs\scandiweb-test-assignment\connect.php on line 8


connect.php
<?php

$host =['localhost']; // name of the host
$dbusername =['root'];   // database user name
$password =[''];   // database password // I added password
$dbname =['test']; // database name
$tblname =['products']; // table of products

$conn = mysqli_connect('$host','$dbusername','$password','$dbname'); // connection 

if(!$conn->connect_error){
    die('Could not Connect MySql Server: '.$conn->connect_error );
}
?>


add.php
<?php
// declare 
$sku = $_POST['sku'];
$name = $_POST['name'];
$price = $_POST['price'];
$productType = $_POST['productType'];
$size = $_POST['size'];
$weight = $_POST['weight'];
$height = $_POST['height'];
$width = $_POST['width'];
$length = $_POST['length'];

// connect to database
include "connect.php";
//insert items to db
$sql = "INSERT INTO products(sku, name, price, productType, size, weight, height, width, length) values('$sku','$name','$price','$productType','$size','$weight','$height','$width','$length')";

if ($conn->query($sql) === TRUE) {
	//echo "ADDED: " . $sku . ", " . $name . ", " . $price, ".$productType.", ".$size.", ".$weight.", ".$height.", ".$width.", ".$length.";		
} else {
	echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
header("Location: ./index.php", TRUE, 301);
exit();


What I have tried:

I've tried changing the code several times, tried a lot of things i got from google and it didn't work (yet)
I know i need to keep reading the manual but it's basic chinese to me. It helps me a lot when i follow tutorials from youtube, but sometimes i dont find my specific error so i don't get an explanation of what's happening (a translated explanation, to me, a beginner)
Posted
Updated 22-Apr-22 5:20am
v2
Comments
CHill60 22-Apr-22 5:20am    
I am not going to follow that link off-site. Post your code here, as code not a photo
Chris Copeland 22-Apr-22 6:33am    
I agree, I won't be following the link either. A picture is no good if we want to copy + paste problematic parts of the code to provide guidance. That being said, I think the error explains itself, you're passing an array into the mysqli_connect parameters when that function does not expect any array values at all.
22bears 22-Apr-22 11:17am    
Hello Chris Copeland. Please take a look, I just posted 2 parts of the code
22bears 22-Apr-22 11:20am     CRLF
Okay so I just updated the post (sorry about the image, now i understand how this website works) Chris Copeland told me mysqli_connect is a function that doesn't expect any array values.. So which parameter should I use? I tried with $conn = new mysqli" but it didn't work either... So i updated the question above and posted the codes

1 solution

PHP
$host =['localhost']; // name of the host

You are declaring $host to be an array containing a single string. Remove the square brackets.
 
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