How do I determine winner in tic tac toe Python?

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Python

I have to write a code for determining winner for my tic tac toe code. Can someone please help me doing it bc i have no idea how to...

below is the codes I have

What I have tried:

def superscript(n):
    out = ""
    while(n>0):
        v = n%10
        if(v==1):
            out = "\u00b9" + out
        elif(v==2 or v==3):
            out = chr(ord("\u00b0")+v) + out
        else:
            out = chr(ord("\u2070")+v) + out
        n //= 10
    return out
    
def printBoard(board):
    for i in range(len(board)):
        if(board[i] == ""):
            print(superscript(i+1),end="")
        else:
            print(board[i],end="")
        
        if(i%3<2):
            print("",end="|")
        elif(i<len(board)-1):
            print("\n-+-+-")
        else:
            print()

def getRow(board, row):
    return board[3*row:3*(row+1)]

def getCol(board, col):
    return [board[col],board[col+3],board[col+6]]

def getDia(board, dia):
    return [board[dia*2],board[4],board[2*(4-dia)]]

def getValidInput(board):
    while(True):
        user = input("Enter a position: ")
        if(len(user)==1):
            if("1"<=user and user<="9"):
                t = int(user)-1
                if(board[t]==""):
                    return t
                else:
                    print("...that position has already been filled\n")                
            else:
                print("...coordinates out of bounds\n")
        else:
            print("...invalid inputs\n")


#determine winner code


board = [""]*9
turn = True
count = 1
winner = ""
t = -1
decorator = t

while(True):
    printBoard(board)
    if(turn):
        print("\nX's turn")
    else:
        print("\nO's turn")

    t = getValidInput(board)
    if turn:
        board[t] = "X"
    else:
        board[t] = "O"



    #DETERMINE WINNER IF ANY, setting winner to the correct value.

    #CHECK IF THERE WAS A WINNER
    
    #CHECK IF TIE

    print("\n\n")


    count += 1
    turn = not(turn)