*Have first a look to 'Solution 2'. It is much easier and universal and in general better ;)*

This is your task to solve to learn c.

Therefore I will not give you the solution, but a hint.

Instanciate two arrays of integers, both with the size N.

Let's name them:

Values // The values you need to evalate Counts // Don't forget to initialize all elements with 0

`Values`

will hold the numbers you need to evaluate.Loop over

`Values`

and count the corresponding number in `Counts`

. Something like:countIx= Values[valueIx] - 1; // Think about why here '-1' Counts[countIx]= Counts[countIx] + 1;

After all that you can loop over

`Counts`

and e.g. show how many time a number occured in `Values`

.**Hint**: What is fundamental here is that the indices of the array Count have a unique relationship to the values in Values. Try to understand the relationship, it has to do with the '-1' mentioned above.

[Edit]

**Important**: Be aware, this solution works only because of the restriction that the numbers to evaluate need to be in the range 1...N.

I hope it gives you an idea.