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arrays are sorted in desending order.then i tried to merge those arrays in desending order and stored it in a third array.third array is not printing.

What I have tried:

#include <stdio.h>

int main() {
// Write C code here
int i,j,size,size2,a[10],b[10],temp,r[20],k;
printf("enter the size of first array");
="" }
="" for(i="0;i<size;i++){
" printf("%d="" ",a[i]);
="" printf("enter="" the="" size="" of="" second="" array");
="" scanf("%d",&size2);
="" scanf("%d",&b[i]);
="" printf("\n");
="" ",b[i]);
="" }
" for(j="i+1;j<size;j++){
" if(a[i]<a[j]){
="" temp="a[i];
" a[i]="a[j];
" a[j]="temp;
" }
" ",a[i]);
" if(b[i]<b[j]){
="" b[i]="b[j];
" b[j]="temp;
" printf("%d",b[i]);
" if(a[i]="">b[j]){

Updated 11-Aug-22 7:06am
Patrice T 9-Aug-22 21:08pm    
I fear part of your code is missing.
use this tag <pre lang="C++"></pre> and paste your code again.

Use Improve question to update your question.
So that everyone can pay attention to this information.
Rick York 10-Aug-22 2:40am    
I tried to correct the formatting but there is so much code missing I decided not save what I did.

One recommendation : learn how to write the sorting as a function because that code appears twice.


is missing!

// more content
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What Luc has said is correct, but you would have been able to spot the problem for yourself if you had spent a few minutes with the debugger.

Think of the development process as writing an email: compiling successfully means that you wrote the email in the right language - English, rather than German for example - not that the email contained the message you wanted to send.

So now you enter the second stage of development (in reality it's the fourth or fifth, but you'll come to the earlier stages later): Testing and Debugging.

Start by looking at what it does do, and how that differs from what you wanted. This is important, because it give you information as to why it's doing it. For example, if a program is intended to let the user enter a number and it doubles it and prints the answer, then if the input / output was like this:
Input   Expected output    Actual output
  1            2                 1
  2            4                 4
  3            6                 9
  4            8                16
Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:
int Double(int value)
   return value * value;

Once you have an idea what might be going wrong, start using the debugger to find out why. Put a breakpoint on the first line of the method, and run your app. When it reaches the breakpoint, the debugger will stop, and hand control over to you. You can now run your code line-by-line (called "single stepping") and look at (or even change) variable contents as necessary (heck, you can even change the code and try again if you need to).
Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
Hopefully, that should help you locate which part of that code has a problem, and what the problem is.
This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!
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Apart from the fact that the fields only hold a maximum of 10 elements, which is not checked anywhere, there are also several nonsensical places, like this one:
for (i=0; i<size; i++){
  for (i=0; i<size2-1; i++){

The C standard does not define a default value for non-static local variables, so k must be either static, global, or initialized.

You are doing a loop like this:

for(i=j=k=0; (i < size) && (j < size2); k++) { ...

What happens when the end of one array is reached with the data from the other?
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