You need to write a custom converter to handle this:
How to write custom converters for JSON serialization - .NET | Microsoft Learn[
^]. I have also written an article on writing custom converters:
Working with System.Text.Json in C#[
^]
Here is the converter:
public class DictionaryConverter : JsonConverter<PartDetails>
{
public override PartDetails? Read(ref Utf8JsonReader reader,
Type typeToConvert, JsonSerializerOptions options)
{
if (reader.TokenType != JsonTokenType.StartObject)
return default;
PartDetails? result = new();
while (reader.TokenType != JsonTokenType.EndArray)
{
reader.Read();
if (reader.TokenType == JsonTokenType.StartObject)
{
string key = string.Empty, value = string.Empty;
foreach (KeyValuePair<string, JsonNode?> item in
JsonSerializer.Deserialize<JsonObject>(ref reader,
options)!)
{
if (item.Key == "key") key = item.Value!.ToString();
if (item.Key == "value") value = item.Value!.ToString();
}
result.Items.Add(key, value);
}
}
reader.Read();
return result;
}
public override void Write(Utf8JsonWriter writer, PartDetails value,
JsonSerializerOptions options)
{
throw new NotImplementedException();
}
}
The class used with the converter attached:
[JsonConverter(typeof(DictionaryConverter))]
public class PartDetails
{
public Dictionary<string, string> Items { get; set; } = new();
}
NOTE: We can't use the attribute
JsonPropertyName
on the class, so we need to tell the serializer to ignore case:
JsonSerializerOptions options = new()
{
PropertyNameCaseInsensitive = true,
};
Now we can deserialize the Json data...
PartDetails? list =
JsonSerializer.Deserialize<PartDetails>(rawJson, options);
foreach (KeyValuePair<string, string> item in list!.Items!)
Console.WriteLine($"{item.Key}, {item.Value}");