How do I get this integer counting function to work with 0

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Quick python question if someone could help.

Below is a python function to count the number of digits. The function works except for one integer, 0.

How can I change this function so it also works for 0

Any feedback would be appreciated

Thank you

def counter(num):
  count = 0
  while num != 0:
    count = count+1
    num = num//10
  return count

counter(0)

What I have tried:

I dont know how else to address this problem

Posted 14-Oct-22 3:16am

Ammar Basheer

Updated 14-Oct-22 4:06am

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OriginalGriff · Accepted Answer · 2022-10-14T04:06:00

Do a zero check before you enter the loop: if it's zero, return one immediately.

Alternatively, use logarithms to get the digits count:

Python

import math
def counter(num):
   if (num == 0):
      return 1
   return int(math.log10(num)) + 1
print(counter(0))
print(counter(1))
print(counter(12))
print(counter(123))
print(counter(1234))
print(counter(12345))
print(counter(123456))
print(counter(1234567))

How do I get this integer counting function to work with 0

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How do I get this integer counting function to work with 0

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