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When implementing the following class:
public class MyClass
   private readonly int myInt = 4;
      if (myInt != 4)
         throw new Exception();

Is it possible for a condition to occur in which the exception will be thrown? Obviously I'm concerned with premature disposal of field values during instance destruction. It'd make sense to me if this were reliable but I'd love to have a second opinion on this.
Posted 28-Jan-13 0:40am
CHill60 28-Jan-13 7:07am
The behaviour of the exception in the destructor will depend on which version of .NET you are using - a generalisation would be expect your application to terminate. You are better off using the IDisposable pattern
Hoogdraaed 28-Jan-13 7:23am
Thanks for your reply, Chill60. So you're saying that I should implement IDisposable, implement the 'myInt'-retrieval in the Dispose()-method, and call the Dispose()-method in the class destructor?
CHill60 28-Jan-13 7:46am
Absolutely - see Edo's solution for reasons why

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Solution 1

Exceptions that occur during destructor execution are worth special mention. If an exception occurs during destructor execution, and that exception is not caught, then the execution of that destructor is terminated and the destructor of the base class (if any) is called. If there is no base class (as in the case of the object type) or if there is no base class destructor, then the exception is discarded.

See this [^] MSDN article

Hoogdraaed 28-Jan-13 7:30am
Thanks for the advice Edo, that is definitely something I haven't put any thought into and it justifies my doubts about this implementation style in the first place. I'm going to have to look for a different course of action.

Regardless of the fact that it seems to make sense, can you cite an official source for me where this is explicitly stated?
Edo Tzumer 28-Jan-13 7:35am
Hoogdraaed 28-Jan-13 7:41am
Edo, thank you very much.
Edo Tzumer 28-Jan-13 7:57am
NP, I like seeing guys that think deeply into code writing techniques :)
good luck mate

And I give you 5+ on the Q

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