Regex "label:.+? $(.+? )\..+? $$.+? Found.+? @\1" works not as I asume

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Hello,
I'm new to this forum and not very familiar with regex syntax.
I hope to get some help and tips here :-)
I am trying to find matches in strings that look like this:

Quote:

Any kind of text blablabla
Label: this url (abc.def.com)
any text
salkdj
Label: this url (asgd.xyz.org)
any text askjfh
found:check@xyz.org

What I need to match is

Quote:

Label: this url (asgd.xyz.org)
any text askjfh
found:check@xyz.

But what I get is nothing!

What I have tried:

I'm using regexr.com for testing.
I tried
/Label:.+?$(.+?)\..+?$$.+?found.+?@\1/gms
but this ends up with no match.
When I remove the reference to the group "\1" at the end of the search string then I get this match

Quote:

Label: this url (abc.def.com)
lkasjdlskjdnh ushdua
salkdj
Label: this url (asgd.xyz.org)
askjfh
found:check@

But this is also not, what I need.
It seems to me as if the ".+?" preceding the "found" is not lazy.
And I don't understand, why the group reference evaluates to no match. What would be the right syntax to achieve my expected result?
Any help appreciated.
kind regards
Georg

Posted 8-Nov-23 0:36am

gcokdepo

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3 solutions

Solution 5

A problem is that you want to match only second label to the end, and sinxe "any text" includes "label", you need to tell.
Try

Label:.+(Label:.+found.+)

Quote:
I'm not very familiar with regex syntax.

Just a few interesting links to help building and debugging RegEx.
Here is a link to RegEx documentation:
perlre - perldoc.perl.org[^]
Here is links to tools to help build RegEx and debug them:
.NET Regex Tester - Regex Storm[^]
Expresso Regular Expression Tool[^]
RegExr: Learn, Build, & Test RegEx[^]
Online regex tester and debugger: PHP, PCRE, Python, Golang and JavaScript[^]
This one show you the RegEx as a nice graph which is really helpful to understand what is doing a RegEx: Debuggex: Online visual regex tester. JavaScript, Python, and PCRE.[^]
This site also show the Regex in a nice graph but can't test what match the RegEx: Regexper[^]

Posted 9-Nov-23 22:25pm

Patrice T

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard Deeming · Accepted Answer · 2023-11-08T01:27:00

This seems to work given your input and expected output:

RegEx

Label:[^(]+\([^.]+\.([^)]+)\).*found:[^@]+@\1

Demo[^]

Literal text "Label:";
Any character other than an open bracket, one or more times;
Literal text "(";
Any character other than a ".", one or more times;
Literal text ".";
Any character other than a closing bracket, one or more times, captured as group 1;
Literal text ")";
Anything at all, zero or more times;
Literal text "found:";
Any character other than "@", one or more times;
Literal text "@";
The same text captured in group 1;

However, your precise requirements aren't entirely clear. For example, does the "found" email always have the domain from the "label" line with just the first segment removed?

gcokdepo · Accepted Answer · 2023-11-09T10:56:00

Hi Richard, I apologise if I have done anything wrong.
Firstly: I'm sorry if I left an unsatisfactory comment, that was not at all intentional. The solution to my problem was the "trick" of using the combination "[^(]" and "\(". That solved my problem with the \1 group. So I am satisfied.
(As I said, I'm not very familiar with regex)
Secondly: I wanted to apologise with my comment for coming up with a silly, simple example. If that was misleading, I apologise.
Kind regards
Georg

Regex "label:.+? \((.+? )\..+? \)$.+? Found.+? @\1" works not as I asume

3 solutions

Solution 1

Solution 5

Solution 3

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Regex "label:.+? \((.+? )\..+? \)$.+? Found.+? @\1" works not as I asume

3 solutions

Solution 1

Solution 5

Solution 3

Add your solution here

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