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equality operator in string in c++

Rahul from Poona asked:

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//Case 1
char * p = "ram" ;

//compare it with a constant literal string
if( p == "ram")
  int i= 1;

char* q = new char[4];

//compare string q with constant literal string
if( q == "ram")
    int i=2;

In the above code snippet in C++, I found that in case1, if condition evaluates to true and it enters the condition1 while in case2 when I was allocating q pointer dynamically then if condition evaluates to false and it does not enter in the condition2. Can anyone please explain this behaviour of char* with equality operator.
Tags: C++


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