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Hi, how can I get the state has sent data from this code? Sending to http server "post" method is working, but I still can not gain status in the running. Someone wrote me that just "readbytes / filelenght" It is obvious, but how do actually read bytes? I tried almost all ways and still nothing. If I remember correctly, the server will write data by "requestStream.Write (tempBuffer, 0, tempBuffer.Length)," and precisely requestStreamu I do not go getting any data. Please advice.

using System;
using System.Collections.Generic;
using System.Text;
using System.IO;
using System.Net;
using System.Collections.Specialized;
using System.Threading;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Windows.Forms;

namespace upload_WithDetails
    public partial class Form1 : Form
        public Form1()

        private void Form1_Load(object sender, EventArgs e)

        private delegate void UpdateProgessCallback(Int64 BytesRead, Int64 TotalBytes);

        public void UploadFilesToRemoteUrl(string url, string file, string logpath, NameValueCollection nvc)
            FileInfo f = new FileInfo("FilePath");

            Int64 fileSize = f.Length;
            long length = 0;
            string boundary = "----------------------------" +

            HttpWebRequest httpWebRequest2 = (HttpWebRequest)WebRequest.Create(url);
            httpWebRequest2.ContentType = "multipart/form-data; boundary=" +
            httpWebRequest2.Method = "POST";
            httpWebRequest2.KeepAlive = true;
            httpWebRequest2.Credentials =

            Stream memStream = new System.IO.MemoryStream();

            byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" +
            boundary + "\r\n");
            string formdataTemplate = "\r\n--" +/* boundary +*/ "\r\nContent-Disposition: form-data; name=\"{0}\";\r\n\r\n{1}";

            foreach (string key in nvc.Keys)
                string formitem = string.Format(formdataTemplate, key, nvc[key]);
                byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
                memStream.Write(formitembytes, 0, formitembytes.Length);

            memStream.Write(boundarybytes, 0, boundarybytes.Length);

            string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\n Content-Type: application/octet-stream\r\n\r\n";

            string header = string.Format(headerTemplate, 
                  "form_upload", file);

            byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);

            memStream.Write(headerbytes, 0, headerbytes.Length);

            FileStream fileStream = new FileStream(file, FileMode.Open,
            byte[] buffer = new byte[2048];

            int bytesRead = 0;

            while ((bytesRead = fileStream.Read(buffer, 0, 
                    buffer.Length)) != 0)
                memStream.Write(buffer, 0, bytesRead);

            memStream.Write(boundarybytes, 0, boundarybytes.Length);

            httpWebRequest2.ContentLength = memStream.Length;

            Stream requestStream = httpWebRequest2.GetRequestStream();

            memStream.Position = 0;
            byte[] tempBuffer = new byte[memStream.Length];

            memStream.Read(tempBuffer, 0, tempBuffer.Length);

            requestStream.Write(tempBuffer, 0,


            WebResponse webResponse2 = httpWebRequest2.GetResponse();

            Stream stream2 = webResponse2.GetResponseStream();
            StreamReader reader2 = new StreamReader(stream2);

            httpWebRequest2 = null;
            webResponse2 = null;


        private void button1_Click(object sender, EventArgs e)

        NameValueCollection myCol = new NameValueCollection();
        string file;

        private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
            myCol.Add("FileName", "1");
            file = "FilePath";            
               file, "FolderPath", myCol);

        private void backgroundWorker1_RunWorkerCompleted(object sender,RunWorkerCompletedEventArgs e)

Updated 31-Jan-10 21:37pm

1 solution

I think I have already answered the same question long ago here.

The problem with you is actually you are sending the total stream at a time.

You need to send in parts. Does this server supports TCP file transfer ?
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