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Hi All ,

I want to create List View control as we can see here :*[^]

or In this site[^]

In MVC- 4 Razor technology.

Please help me.


Posted 11-Apr-13 5:16am
Sandeep Mewara 11-Apr-13 12:50pm
Tried anything so far?
kapilonkar 12-Apr-13 2:44am
Hi Sandeep ,

Thanks for reply

No I am bit New to mvc , I have searched for using ListView in MVC but yet haven't got code snippet matching to my requirement using MVC razor.
please help me if you have an idea of how to do it.
Thanks anyways :)
Member 9802658 9-May-13 7:07am
my simple solution to paging in mvc4


1 solution

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Solution 1

@model IEnumerable<organizationmanagementsystem.models.employeemastermodel>

ViewBag.Title = "Index2";
Layout = "~/Views/Shared/_Layout.cshtml";
ViewBag.maxPage = (ViewBag.recordsCount % OrganizationManagement.Common.Constants.rowsPerPage == 0) ? (ViewBag.recordsCount / OrganizationManagement.Common.Constants.rowsPerPage) : ((ViewBag.recordsCount / OrganizationManagement.Common.Constants.rowsPerPage) + 1);

<script src="~/Scripts/jquery.jqpagination.min.js"></script>

<script type="text/javascript">
$(document).ready(function () {

link_string: '~/Index2/?page={page_number}',
max_page: @ViewBag.maxPage,
paged: function (page) {
url: '@Url.Action("/Index2")',
type: "GET",
data: {currentPage:page},
success: function (result) {
var $response = $(result);

//Query the jQuery object for the values
var tableValue = $response.find('#StatusIndex').html();





@Html.ActionLink("Create New", "Create")

@using (Html.BeginForm("Index2", "Employee"))


<input type="submit" value="Search" />


@foreach (var item in Model) {


@Html.DisplayNameFor(model => model.EmployeeName)

@Html.DisplayNameFor(model => model.LocationName)

@Html.DisplayNameFor(model => model.DepartmentName)

@Html.DisplayNameFor(model => model.DOJ)

@Html.DisplayFor(modelItem => item.EmployeeName)

@Html.DisplayFor(modelItem => item.LocationName)

@Html.DisplayFor(modelItem => item.DepartmentName)

@Html.DisplayFor(modelItem => item.DOJ)

@Html.ActionLink("Edit", "Create", new { id=item.Id }) |
@Html.ActionLink("Details", "Details", new { id=item.Id }) |
@Html.ActionLink("Delete", "Delete", new { id=item.Id })


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