Click here to Skip to main content
15,663,154 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
See more:
Dear All,

I have my xml file with rootnode as "Base" and I have my attribute "Name" available in the root node itself. I need to find out my attribute value located in my root node. How could I proceed, please help me ASAP. For your reference I hereby providing you a sample.

<Baseclass ID="5" Name="Raj">
Updated 22-May-13 19:22pm

Try this
XDocument xDoc = XDocument.Load("path to xml");
var TagIds = xDoc.Descendants()
                .Where(e => 
                            e.HasAttributes && 
                            e.Name.LocalName.Equals("Baseclass") && 
                            e.Attribute("ID") != null)
                .Select(e => e.Attribute("ID").Value);

Hope this helps
Share this answer
Jameel VM 23-May-13 1:33am    
I have updated my answer..please try that
rahulaaditya 24-May-13 9:50am    
Many thanks to you Jameel for your help.
Dim tempPath As String = FolderBrowserDialog1.SelectedPath & "\" & ListBox1.Items(x).ToString

Dim xSid = From xattr In xDoc.Descendants("Baseclass") _
Select att = xattr.Attribute("Name").Value
sSID = xSid.ElementAt(0).ToString 'SID value
Share this answer

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900