Not inserting values in database

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Here is the code:

protected void cmdLogin_Click(object sender, EventArgs e)
{

Class1.con = CreateConnection();
string str = "SELECT Ad_Regid from Admin_Profile WHERE Ad_Regid LIKE @TempPasscode";
cmd = new SqlCommand(str, Class1.con);

cmd.Parameters.AddWithValue("@TempPasscode", txtcurrentpwd.Text.Trim());
SqlDataReader dr = cmd.ExecuteReader();

if (dr.Read())
{
if (dr[4].ToString() == txtcurrentpwd.Text)
{
cmd = new SqlCommand("_insertAdminLogin", Class1.con);
cmd.CommandType = System.Data.CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@AdminType", ddltype.SelectedItem.Text);
cmd.Parameters.AddWithValue("@AdminUsrname", txtuname.Text);
cmd.Parameters.AddWithValue("@AdminPwd", txtconfirmpwd.Text);
cmd.ExecuteNonQuery();

}
else
{
ClientScript.RegisterStartupScript(GetType(), "Warning", "javascript:alert('Temporary Password Does not Match!');", true);
}

}

Sp:
CREATE PROCEDURE [dbo].[_insertAdminLogin]
(
@AdminType VARCHAR(100),
@AdUsrname VARCHAR(12),
@AdminPwd varchar(12)

)
AS BEGIN

INSERT INTO dbo.AdminLogin (AdminType, AdminUsrname, AdminPwd)

VALUES (@AdminType, @AdUsrname, @AdminPwd)

END

}

Posted 5-Jul-13 17:20pm

Sugu Thomas

Updated 5-Jul-13 17:27pm

v2

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[no name] 6-Jul-13 1:34am

What type of error you are getting?

3 solutions

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Zafar A khan · Answer 1 · 2013-07-05T18:55:00

try this

C#

Class1.con = CreateConnection();
string str = "SELECT Ad_Regid from Admin_Profile WHERE Ad_Regid LIKE @TempPasscode";
cmd = new SqlCommand(str, Class1.con);
if(Class1.con.State==ConnectionState.Closed)
Class1.con.Open();
cmd.Parameters.AddWithValue("@TempPasscode", txtcurrentpwd.Text.Trim());
SqlDataReader dr = cmd.ExecuteReader();

if (dr.Read())
{
if (dr[4].ToString() == txtcurrentpwd.Text)
{
cmd = new SqlCommand("_insertAdminLogin", Class1.con);
if(Class1.con.State==ConnectionState.Closed)
Class1.con.Open();
cmd.CommandType = System.Data.CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@AdminType", ddltype.SelectedItem.Text);
cmd.Parameters.AddWithValue("@AdminUsrname", txtuname.Text);
cmd.Parameters.AddWithValue("@AdminPwd", txtconfirmpwd.Text);
cmd.ExecuteNonQuery();

}

**Nirav Prabtani** · Answer 2 · 2013-07-05T19:29:00

C#

protected void cmdLogin_Click(object sender, EventArgs e)
{
 
Class1.con = CreateConnection();
string str = "SELECT Ad_Regid from Admin_Profile WHERE Ad_Regid LIKE '%'"+@TempPasscode+"'%'";
cmd = new SqlCommand(str, Class1.con);

cmd.Parameters.AddWithValue("@TempPasscode", txtcurrentpwd.Text.Trim());
SqlDataReader dr = cmd.ExecuteReader(); 

if (dr.Read())
{
if (dr[4].ToString() == txtcurrentpwd.Text)
{
cmd = new SqlCommand("_insertAdminLogin", Class1.con);
cmd.CommandType = System.Data.CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@AdminType", ddltype.SelectedItem.Text);
cmd.Parameters.AddWithValue("@AdminUsrname", txtuname.Text);
cmd.Parameters.AddWithValue("@AdminPwd", txtconfirmpwd.Text);
cmd.ExecuteNonQuery();

}
else
{
ClientScript.RegisterStartupScript(GetType(), "Warning", "javascript:alert('Temporary Password Does not Match!');", true);
}

} 
 
Sp:
CREATE PROCEDURE [dbo].[_insertAdminLogin]
(
@AdminType VARCHAR(100),
@AdUsrname VARCHAR(12),
@AdminPwd varchar(12)


)
AS BEGIN

INSERT INTO dbo.AdminLogin (AdminType, AdminUsrname, AdminPwd)

VALUES (@AdminType, @AdUsrname, @AdminPwd)
 
END 
 

 

}

hebsiboy · Answer 3 · 2013-07-05T21:11:00

You Just Try This Code

C#

protected void cmdLogin_Click(object sender, EventArgs e)
{
 
Class1.con = CreateConnection();
string str = "SELECT Ad_Regid from Admin_Profile WHERE Ad_Regid LIKE @TempPasscode";
        cmd = new SqlCommand(str, Class1.con);
        con.Open();
        cmd.Parameters.AddWithValue("@TempPasscode", txtcurrentpwd.Text.Trim());
        cmd.CommandType = CommandType.Text;
        SqlDataReader dr = cmd.ExecuteReader();

        if (dr.Read())
        {
            if (dr[4].ToString() == txtcurrentpwd.Text)
            {
                cmd = new SqlCommand("_insertAdminLogin", Class1.con);
                cmd.CommandType = System.Data.CommandType.StoredProcedure;
                cmd.Parameters.AddWithValue("@AdminType", ddltype.SelectedItem.Text);
                cmd.Parameters.AddWithValue("@AdminUsrname", txtuname.Text);
                cmd.Parameters.AddWithValue("@AdminPwd", txtconfirmpwd.Text);
                cmd.ExecuteNonQuery();
                con.Close();

            }
            else
            {
                ClientScript.RegisterStartupScript(GetType(), "Warning", "javascript:alert('Temporary Password Does not Match!');", true);
            }
        }

)

AS BEGIN

INSERT INTO dbo.AdminLogin (AdminType, AdminUsrname, AdminPwd)

VALUES (@AdminType, @AdUsrname, @AdminPwd)

END

}

Not inserting values in database

3 solutions

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Solution 2

Solution 3

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