Need a Query to get the Following Output

Question

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This is My table(Fee) Containing some Rows

Id	Installment_No	Amount_Paid
1000	1	         6000
1000  	2	         6000
1001	1	         12000
1002	1	         6000
1003	1	         6000
1004	1	         6000
1005	1	         6000
1005	2	         6000
1006	1	         12000

I just need a Query to get the Below output.

Output		
Id	Installment_No	Amount_Paid
1002	1	        6000
1003	1	        6000
1004	1	        6000

Id "1000" had paid 12000 Rupees in Two Installments(So i don't want this)

and

Id "1001" had Paid 12000 Rupees in one Installment Only(this one also i don't need)

and

Id "1002" had Paid only 6000 rupees in 1st Installment need to pay remaining 6000 Rupees(I want this type Details)

I tried it but i couldn't get the Output.

Please tell me the Solution......

Posted 6-Aug-13 2:34am

Venkat Kumar chigulla

Updated 6-Aug-13 2:37am

Richard MacCutchan

v2

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Comments

Richard MacCutchan 6-Aug-13 8:38am

Maybe if you show what you have tried, and explain what is not working, then people will try to help you.

Venkat Kumar chigulla 6-Aug-13 8:43am

I tried this Query

select Admission_ID from Tution_Fee where Branch_Code='ap' and Amount_Paid!='12000' and Installment_No!=2 and Admission_ID in (

select Admission_ID from Admissions where Branch_Code='ap' and Batch_ID='1556')

I got the Records who paid 12000.
Example: 1000 id will come in the output( He paid 12000)

Karwa_Vivek 6-Aug-13 8:59am

According to your Question you want the Records ,who have not paid there total Installments yet and who have to pay the Remaining Installments ,Right ??

2 solutions

Solution 1

looks like you are just looking for where the amount paid is less than 12000.

SQL

SELECT Id, Installment_No, Amount_Paid
FROM Fee
Where (AmountPaid < 12000);

Posted 6-Aug-13 4:32am

someoneseth

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Pandiaraj_4u · Accepted Answer · 2013-08-06T04:34:00

Solution 2

You can try like below.... It will help you...

SQL

SELECT * FROM FEE WHERE ID IN (SELECT id
  FROM FEE
WHERE amt=6000 
GROUP BY id
HAVING COUNT(id) = 1)

Fiddle Example : http://www.sqlfiddle.com/#!3/87471/2

Posted 6-Aug-13 4:34am

Pandiaraj_4u

Comments

Venkat Kumar chigulla 7-Aug-13 2:45am

Thank you so Much. It's working and thanks a lot