Regular Expression to accept alphanumeric values

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Hi All,

I am looking for a Regex which accepts values like shown below:Please help. I tried this
^[a-zA-Z0-9'\s]

but not working. I dont want to accept any symbols other than space.

2565334589
132 258 6589
821222296B01

Thanks a lot.

Posted 20-Aug-13 9:52am

vidkaat

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Sergey Alexandrovich Kryukov 20-Aug-13 15:54pm

You probably meant to say "I dont want to accept any symbols other than blank space, digits and Latin letters"...
—SA

2 solutions

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ridoy · Accepted Answer · 2013-08-20T10:03:00

Solution 1

Just try this one:

C#

"^[0-9a-zA-Z ]+$"

Posted 20-Aug-13 10:03am

ridoy

Comments

Maciej Los 20-Aug-13 16:30pm

+5!

ridoy 20-Aug-13 16:34pm

Thanks Maciej,:)

Sergey Alexandrovich Kryukov 20-Aug-13 16:42pm

Same thing, 5ed.
—SA

ridoy 21-Aug-13 1:53am

Thank you,SA.

ridoy 21-Aug-13 2:03am

Thank you,SA.

Sergey Alexandrovich Kryukov · Accepted Answer · 2013-08-20T10:03:00

Solution 2

Try ^([a-zA-Z0-9 ])+$.

Probably, you can see you mistakes. You forgot about multiplicity (I used '+' meaning "one or more"), and probably misspelled '$' as 's'. You added a note about blank space below your expression but did not try to include this character.

Note that "alphanumeric" maybe not exactly what I want. As .NET supports Unicode "alpha" may refer to much wider set of letters than Latin characters you tried to allow. :-)

—SA

Posted 20-Aug-13 10:03am

Sergey Alexandrovich Kryukov

Updated 20-Aug-13 10:42am

v3

Comments

ridoy 20-Aug-13 16:23pm

+5 SA for explaining it,possibly you and me solve it in same time! :)

Sergey Alexandrovich Kryukov 20-Aug-13 16:43pm

Yes, thank you. I up-voted yours.
—SA

Maciej Los 20-Aug-13 16:30pm

+5!

Sergey Alexandrovich Kryukov 20-Aug-13 16:43pm

Thank you, Maciej.
—SA