Regular expression to validate phone number

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i want a regular expression to validate this format of pnone number any help

961_(71 or 72 or 76 or 79 or 3)_and 6 digits number [0-9]

example: 96171648262,9613635241

thanks,

Posted 3-Sep-13 22:23pm

Hidhoud1991

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2 solutions

Solution 2

use this code

VB

Public  Function ValidatePhone(sPhone As String) As Boolean
    Dim sReg As New System.Text.RegularExpressions.Regex("961(71|72|76|79|3)\d{6}")
    If sReg.IsMatch(sPhone) Then
        Return True
    Else
        Return False
    End If
End Function

Posted 3-Sep-13 23:26pm

Menon Santosh

Updated 4-Sep-13 0:08am

v2

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OriginalGriff · Accepted Answer · 2013-09-03T22:34:00

Solution 1

Try:

961(71|72|76|79|3)\d{6}

"how could i use it in vb.net to validate a string"

VB

Dim validate As New Regex("961(71|72|76|79|3)\d{6}")
Dim inp As String = "96171648262"
If validate.Match(inp).Success Then
    ...
End If

Posted 3-Sep-13 22:34pm

OriginalGriff

Updated 3-Sep-13 23:00pm

v2

Comments

[no name] 4-Sep-13 4:39am

how could i use it in vb.net to validate a string

OriginalGriff 4-Sep-13 5:00am

Answer updated

[no name] 4-Sep-13 5:18am

thanks it works

OriginalGriff 4-Sep-13 5:24am

You're welcome!

[no name] 4-Sep-13 5:30am

it fail on this number 96130000560.. this number has 7 digits after the (3) it should have 6 only

OriginalGriff 4-Sep-13 5:36am

Ah! Try adding start and end marker to the string:
^961(71|72|76|79|3)\d{6}$

[no name] 4-Sep-13 5:40am

it didnt work ... it took all the numbers as invalid even if the number is valid

OriginalGriff 4-Sep-13 6:21am

Show me exactly what code you are using - including where you get the input string from.