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how to show online users my application? i'm using SQL table to store username and passwords.please help me.
Shubham Choudhary 8-Oct-13 4:08am
Hi @amnk !!!
If u have table like username and password so make a flag or use bool value to insure who user is log in or log out like
blool value= 1;
bool value=0;
and then count the true value and show it
} 8-Oct-13 4:56am
thanks. i will try

Refer -

1. How to check in ASP.NET if the user is online?[^]

The ASP.NET Membership service supports this feature. To get the particular user's last activity date, use LastActivityDate property and to indicate whether the user is online or not use IsOnline property. Also to get the number of online users, use GetNumberOfOnlineUsers. Of course, the ASP.NET Membership service does not save the last IP address, and you have to override some behavior of SqlMembershipProvider in this case.

2. Show Online Users/Visitors in ASP.Net website[^]
Comments 8-Oct-13 5:04am
Thanks Tadit. I will try
Most Welcome.

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Check similar CP thread first:
How to see who is online in website c#[^]

Then i should say, if you use Membership[^] then simply call Membership.GetNumberOfUsersOnline[^].

Also view:
Get online users in ASP.NET[^]
Comments 8-Oct-13 6:22am
Thanks for help. i will try
ridoy 8-Oct-13 6:44am
will be glad if those can help you.
Display the number of users/sessions currently active your website.
Using the Session_Start and Session_End Events

Sub Session_Start(ByVal sender As Object, ByVal e As EventArgs)
' Fires when the session is started
Application("UserCount") = Application("UserCount") + 1
End Sub

Sub Session_End(ByVal sender As Object, ByVal e As EventArgs)
' Fires when the session ends 
Application("UserCount") = Application("UserCount") - 1
End Sub
To Display UserCount, add a Label Control to the WebForm, name it lblUserCount

Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
'Put user code to initialize the page here
Me.lblUserCount.Text = "User(s) online " & Application("UserCount")
End Sub

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