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I use

SQL
qry = ""
qry = "SELECT TOP 1 Image FROM T_ImageStore"
cmd = New OleDbCommand(qry, conn)
Dim img As Byte() = DirectCast(cmd.ExecuteScalar(), Byte())
Dim ms As MemoryStream = New MemoryStream(img)
PictureBox1.Image = Image.FromStream(ms)


this code to retrieve image from database and display in picture Box.

I get an error when PictureBox1.Image = Image.FromStream(ms) line encounted

The bug is

An unhandled exception of type 'System.ArgumentException' occurred in System.Drawing.dll

Additional information: Parameter is not valid.

I couldn't find what the error is, Can any 1 help in this pls,

Thanks
Posted
Comments
Thava Rajan 13-Nov-13 4:39am    
seems there might be a data loss at the time of insert or update,or else is this happens for the first image or when the second image loaded

void DispalyImage()
    {

        SqlDataAdapter da = new SqlDataAdapter(cmd);
        DataSet ds = new DataSet();
        da.Fill(ds, "Images");
        int count = ds.Tables["Images"].Rows.Count;

        if (ds.Tables.Count > 0 && ds.Tables[0].Rows.Count > 0)
        {
            var data = (Byte[])(ds.Tables["Images"].Rows[count - 1]["Image"]);
            MemoryStream stream = new MemoryStream(data);
            pictureBox1.Image = Image.FromStream(stream);
        } 

    }
 
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Dim myMS As New IO.MemoryStream

PictureBox1.Image = System.Drawing.Image.FromStream(myMS)


I hope, It will help for you........
 
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