Scaling mouse position

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Hello,

I'm making a remote desktop program and in order to control the remote screen with my mouse i need to be able to send over the correct coordinates taking into consideration the size of my form.
In more detail, I will be moving my cursor over my form and my mouse position will be sent to the client so their mouse can move. If my form has the size (300,300) and the client's screen size is (1281,761), if i move my mouse to 300,300 on the form then their mouse should move to 1281,761, and if i move the mouse to 150,150 then the client's should move to ~640,380.

Does anyone have a code for this please? (I can't work out the math behind it). To test this on my own computer i'm settings label1.location to wherever the client mouse should go.

Please help!

Posted 17-Nov-13 6:52am

Rixterz123

Updated 21-Nov-13 5:57am

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Sergey Alexandrovich Kryukov 17-Nov-13 14:21pm

Not clear. I believe you can only implement RDP if you control the remote system with the screen of identical size (which you can simulate by using a part of bigger screen on the client part) or at least the same aspect ratio. But then this is a simple linear transform of coordinates. How can it be a problem?
—SA

[no name] 17-Nov-13 14:58pm

i don't understand how you can put your mouse in the top left of the form and the client's mouse goes to the top left of the screen.

Sergey Alexandrovich Kryukov 17-Nov-13 15:08pm

Client is the part which controls the remote computer, and remote computer is server.
Now, when you move your mouse on the left, your server host mouse is not moved directly, it moves through the RDP protocol, so you can do the transform on the fly...
—SA

[no name] 17-Nov-13 15:16pm

i'm making my own RDP, not using other people's, and i'm also using VB.net

Sergey Alexandrovich Kryukov 17-Nov-13 17:34pm

Of course! I perfectly understand and fully respect that. But the problem you are trying to ask about looks so trivial that I though it might be useful to see how and RDP client is implemented by people who did not have to ask anyone about how to implement it... :-)
—SA

[no name] 17-Nov-13 15:19pm

and what needs clarifying? let's try this: i'm controlling your computer. you have a notepad window open and i want to close it from my end. Your screen's size is, let's say, (1000,700). The size of the form that i'm viewing your screen on is (500,500). If i want to close your notepad window then I can't send you the coordinates of the X as that's just where I see it because the mouse position sent has not had the ratio difference applied to it. So i wouldn't be able to close that pesky notepad window.

Sergey Alexandrovich Kryukov 17-Nov-13 17:39pm

No, this is me who would have to ask what do I need to clarify.
You need to do the transformation on the fly:
x = M[0,0] + M[0,1]*x
y = M[1,0] + M[1,1]*y
where M is calculated from the sizes of the server-part screen size and client-part client window size.
If you do it correctly, you mouse will be put in a corresponding location of the server part.
Which part is unclear?

Everything is clear about what you need to do, the only unclear and even mysterious part is your background.

—SA

[no name] 18-Nov-13 11:00am

i still don't understand what the [0,1] lark is all about. I also don't understand what you mean by "M is calculated from the sizes..." - what calculation?. Please stop being so vague because by now i thought you would have realised that i understand nothing you ever say.

Let's say the server receives a message of the mouse coordinates. (message is "100,100")
Dim ServerScreenWidth as integer=1000
dim ServerScreenHeight as integer=600
dim ClientFormWidth as integer=700
dim ClientFormHeight as integer=400
Dim ClientCursorX as integer=message.split(",")(0)
Dim ClientCursorY as integer=message.split(",")(1)
Dim XRatio as integer= serverscreenwidth / clientscreenwidth
dim YRatio as integer= serverscreenheight / clientscreenheight
Cursor.Position=New Point(What?, What?)

Sergey Alexandrovich Kryukov 18-Nov-13 12:36pm

Remember your "and what needs clarifying?"? Apparently, this is the array of rank 2, but you can do whatever you want. Everything was explained by the words "linear transform". Do you understand now why I mentioned your background? I'm not "vague" at all, I just assumed that you can do geometry calculation at the level of middle school.
You already did most of the work, not calculate X and Y using simple school algebra...
Look, you seriously need to do it all by yourself, at least once, otherwise you will remain hopeless and never learn how to do simple development, despite the fact that the RDP client work itself is serious enough. Honestly...
—SA

[no name] 18-Nov-13 15:45pm

Hi,
guess what? I got it working! i self-debugged a few times by writing variables out one-by-one until i managed to concatentate them into this:
(the label "speciallabel" is used to show where the server's cursor will go, and i had to use screen.primaryscreen etc as i was testing everything on my computer.)
speciallabel.Location = New Point(Cursor.Position.X * (Me.Width / Screen.PrimaryScreen.WorkingArea.Width), Cursor.Position.Y * (Me.Height / Screen.PrimaryScreen.WorkingArea.Height))

Please take a look at the screenshot here!
www.4shared.com/photo/cejg9L-H/screenshot.html

But seriously, Sergey, I didn't mean to be so, let's say, abrupt. As you may have noticed, I have had a lot of trouble in the past with this project and now it's all repeating itself! Hopefully it'll be smoother from now on...so i thank you for what help you tried to give.

Sergey Alexandrovich Kryukov 18-Nov-13 16:00pm

Did I tell you that you are almost there? Do you see that having it done by yourself is much better?
Congratulations!
—SA

bluusoftware 14-May-22 21:31pm

You know for a developer replying to another developer that needs some support, you would have (IMO) been better off not replying at all. Not just you, but most of the authors of the replies here. Seriously....someone politely asked for some help. They gave as much info as they though would be required (remember...they don't know the solution...that's why they're here...) yet they are met with such sarcasm and duress. If you don't want to help someone, keep your hands in your pockets and don't reply. If you do...then try not to come across as a total a hole. I don't know how many of you that replied drive cars...but if you do...the same principle applies. We were all learners once. If you've got 20 years experience behind you....let someone benefit from it just like you did once. If you've got 1 year of experience but still want to try and help soneone...then good for you and thank you, and if you're answer helps someone then you are a superb human being for taking the time to help someone else. I'm sick of seeing so much angst on this site and others. If you don't have anything nice or positive to say to help someone, keep your 'virtual' mouth shut.

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Sergey Alexandrovich Kryukov · Answer 1 · 2013-11-17T09:13:00

Please see my comments to the question. It's not really clear which part could be your problem. You can take a look at two CodeProject works where this problem is apparently solved:

Remote Desktop using C#.NET[^],
Palantir - Remote Desktop Manager[^].

I especially like the second one, Palantir, and exactly because of the problem related to the one you are concerned with. Some time ago, I prepared the presentation and faced the problem of different screen sizes on two computers. I found that Microsoft Windows RDP client failed to solve the problem nicely, but, to my surprise, Palantir coped with it. So, please check it out.

—SA

Scaling mouse position

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