converting base 10 arithmetic algorithms to base 2 arithmetic algorithms

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So I have a bunch of code I want to reuse, because I saved them up in my hard drive and I don't want to waste time re-implementing them. So I was wondering if I am on the right track. I got the gist of it, but I am trying to make sure I don't run into some problem later on.

In all of my algorithms, I use the variable addToNextSlot and addToSlot. addToNextSlot put a number in the vector after dividing by 10 and addToSlot get the value from %10. So if I understand correctly to do base 2, we just need to change %10 and /10 to %2 and /2, right? How about when I get the value 2 after I add up these 3 rows I get after multiplying a number x with a number y. I would get the value 3 in addToNextSlot, so it's me or I can't reuse my code at all and I have to think this through instead of just changing stuff here and there?

11111111
11111110
11111110

Posted 3-Mar-14 13:47pm

OpenTheTrollGate

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Sergey Alexandrovich Kryukov · Accepted Answer · 2014-03-03T13:51:00

Solution 1

Use those simple calculations on the piece of paper and validate your calculation automatically, working by definition of the notation in different systems:
http://en.wikipedia.org/wiki/Decimal_representation[^],
http://en.wikipedia.org/wiki/Binary_representation[^].

The problem is too basic to spend too much time on it, but this will serve a useful exercise for you.

—SA

Posted 3-Mar-14 13:51pm

Sergey Alexandrovich Kryukov

v2

Comments

CPallini 4-Mar-14 4:19am

5.

Sergey Alexandrovich Kryukov 4-Mar-14 10:07am

Thank you, Carlo.
—SA