Convert a TCL code to C++...

Question

3.00/5 (1 vote)

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for {set i 128} {$i<256} {incr i 1} {
    eval lut SetTableValue $i [expr ($i-128.0)/128.0] [expr ($i-128.0)/128.0] [expr ($i-128.0)/128.0] 1

That's what I got in C++

for (int i; 128<256;i++)>
    eval->lut(SetTableValue(i), expr->(i-128.0)/128.0()expr->(i-128.0)/128.0()expr->(i-128.0)/128.0()1);

I don't know how to change eval->lut and expr functions. Do you know?

I tried to convert a TCL code to C++, but converter that I used didn't translate a very importnat lines of code. Can anyone make it work?

Posted 18-Apr-10 22:50pm

nmatulionis

Updated 20-Jul-10 22:08pm

Richard MacCutchan

v5

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chanel88 · Answer 1 · 2011-09-27T15:05:00

Solution 3

May I know which converter you are using to to convert a TCL code to C++?

Posted 27-Sep-11 15:05pm

chanel88

Phil Martin · Answer 2 · 2010-07-20T18:59:00

for (int i = 128; i < 256; ++i) {

   setTableValue(i, ((double)i - 128.0) / 128), ((double)i - 128.0) / 128), ((double)i - 128.0) / 128), 1);

}

where setTablueValue would look something like:

void setTableValue(int index, double r, double g, double b, double a) {

   data[index].r = r;
   data[index].g = g;
   data[index].b = b;
   data[index].a = a;

}

Saurabh.Garg · Answer 3 · 2010-04-18T23:32:00

Solution 1

nmatulionis wrote:
for (int i; 128<i<256;i++)

This should be:
for(int i=129 ; i<256 ; ++i)

What does eval, lut and expr means in TCL?

-Saurabh

Posted 18-Apr-10 23:32pm

Saurabh.Garg

Updated 20-Jul-10 21:35pm

v2