Click here to Skip to main content
13,046,679 members (60,872 online)
Rate this:
Please Sign up or sign in to vote.
See more:
I want to create Binary tree in TreeView Control from List
Could not find any Logic.
My list as:
List members = getAllMembers();

I tried:
TreeView1.Node.Add(members.First());  //Root Node Add
//TreeNode LeftNode,RightNode;

Now i am getting how to move futher.

//I know the logic for Left child is: 
if (isExists( members[currentNodeIndex * 2])
 LeftNode.Nodes.Add(members[currentNodeIndex * 2]) 
//for Right child
if (isExists( members[(currentNodeIndex * 2) + 1])
 LeftNode.Nodes.Add(members[currentNodeIndex * 2])

I have record of more than 2000 members. I want to display all in hierarichal order in treeview. Could not find proper logic. Please help.
Posted 12-May-10 22:28pm
Updated 12-May-10 23:02pm

1 solution

Rate this: bad
Please Sign up or sign in to vote.

Solution 1

I do not have any idea on how to do this as I am having difficulty in visualizing a TreeView displaying a BinaryTree. It would end up being very, very wide for any tree with a depth greater than about 3.

However I recently bookmarked this[^] for later investigation and offer it in the hope that it might be of use to you.

Good luck! :)

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

  Print Answers RSS
Top Experts
Last 24hrsThis month

Advertise | Privacy | Mobile
Web02 | 2.8.170713.1 | Last Updated 13 May 2010
Copyright © CodeProject, 1999-2017
All Rights Reserved. Terms of Service
Layout: fixed | fluid

CodeProject, 503-250 Ferrand Drive Toronto Ontario, M3C 3G8 Canada +1 416-849-8900 x 100