extracted url does not shows the images

Question

0.00/5 (No votes)

See more:

Hi there,
I am rookie in php and need some help.

what i am trying to do is to extract the url which is as follows:
http://www.weatherzone.co.nz/north-island/wellington

However i am not getting the image tags.

i have done the following.

PHP

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://www.weatherzone.co.nz/north-island/wellington');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
echo $output;

$url="http://www.weatherzone.co.nz/north-island/wellington";

$html = file_get_contents($url);

$doc = new DOMDocument();
@$doc->loadHTML($html);

$tags = $doc->getElementsByTagName('img');

foreach ($tags as $tag) {
  echo $tag->getAttribute('src');
}

This code only gets me the website content but doesnt shows the images from the external url.
Any help would be appreciated!!!
Thanks in advance.

Posted 15-Dec-14 10:53am

Amit Karyekar

Updated 15-Dec-14 19:50pm

Kornfeld Eliyahu Peter

v2

Add a Solution

Comments

Chubby Ninja 15-Dec-14 17:37pm

For some reason I get an error when posting my answer, anyway, the reason you arent getting any results is because weatherzone is blocking file_get_contents.. use cURL and imitate a web browser:

$url="http://www.weatherzone.co.nz/north-island/wellington";
$agent= 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_6_8) AppleWebKit/534.30 (KHTML, like Gecko) Chrome/12.0.742.112 Safari/534.30';

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERAGENT, $agent);
$html = curl_exec($ch);

$doc = new DOMDocument();
$doc->loadHTML($html); // don't suppress errors

$tags = $doc->getElementsByTagName('img');

foreach ($tags as $tag) {
echo $tag->getAttribute('src');
}

Amit Karyekar 15-Dec-14 17:48pm

it doesnt work out
gives an output of
wellington/images/logos/weatherzone_logo_185x36.png/images/widgets
however earlier it was showing the text on web.

2 solutions

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Kornfeld Eliyahu Peter · Answer 1 · 2014-12-15T20:14:00

As you can see image sources are relative URLs in that site, like '/images/logos/weatherzone_logo_185x36.png'...
When you display it in the context of your site it will not be found by the browser as the final URL fill be somethng like 'http://my-site/images/logos/weatherzone_logo_185x36.png', while on the original site it will be 'http://www.weatherzone.co.nz/wellington/images/logos/weatherzone_logo_185x36.png'...

Chubby Ninja · Answer 2 · 2014-12-15T23:20:00

the reason you arent getting any results is because weatherzone is blocking file_get_contents().. use cURL and imitate a web browser:

PHP

$url="http://www.weatherzone.co.nz/north-island/wellington";
$agent= 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_6_8) AppleWebKit/534.30 (KHTML, like Gecko) Chrome/12.0.742.112 Safari/534.30';
 
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_USERAGENT, $agent);
$html = curl_exec($ch);
 
$doc = new DOMDocument();
$doc->loadHTML($html); // don't suppress errors

$tags = $doc->getElementsByTagName('img');

foreach ($tags as $tag) {
echo $tag->getAttribute('src');
}

This prints out the src="" as you've said, so you need to wrap that in img tags and reference their domain - as the images are stored on their website not yours..

PHP

foreach ($tags as $tag) {
echo '<img src="http://www.weatherzone.co.nz' . $tag->getAttribute('src') . '">';
}

extracted url does not shows the images

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

extracted url does not shows the images

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

Existing Members

...or Join us