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using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace WindowsFormsApplication1
    public partial class Form1 : Form

        public Form1()

        private const int id = 10;

        private string[] numArray = new string[id];
        private int index = 0;

          private void button1_Click(object sender, EventArgs e)
                  if (this.index < 10)
                      numArray[this.index] = textBox1.Text;

          private void button2_Click(object sender, EventArgs e)
              for (int i = 0; i < 10; i++)

                  listBox1.Items.Add(numArray[i]); //show array in a listbox


          private void button3_Click(object sender, EventArgs e)

Moved here from comment:

Um yeah actually I just saw that it works if I input exactly 10 strings but I want it to work if I input maybe even less than that..
That was why I was getting the error that it contains a null value
Updated 7-May-15 1:00am
Sascha Lefèvre 7-May-15 5:26am
How does it not work?

The problem is that it does work: it is trying to do exactly what you told it too!

But...integers and strings are different: integers are Value types, and strings are Reference types.

So when you create an array of integers:
int[] myInts = new int[10];
You get an array of ten integers, filled with the default value, which is zero;
But the same code for strings:
string[] myStrings = new string[10];

Creates an array of ten references to strings, filled with teh defautl value for a Referance type, which is null

Try this instead:
for (int i = 0; i < index; i++)
    listBox1.Items.Add(numArray[i]); //show array in a listbox
To avoid the null-reference exception, initialize the array-indices in the constructor of your form with empty strings (after InitializeComponent()).

If you would use a List<string> instead of the array, you could circumvent that problem altogether, because you don't have to specify the size of the List beforehand and it will have exactly the size of how many strings you've added to it.

Dakota335 7-May-15 6:24am
Thank you so much. It helped solve my problem
Sascha Lefèvre 7-May-15 6:26am
You're welcome!

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

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