Why is the output different in C program

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1.00/5 (3 votes)

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C++

#include<stdio.h>
#include<conio.h>
void main()
{       
    clrscr();
    char a[3]="lk";
    printf("%c",a[3]);
    getch();
}

Instead of getting lk as output, I get the output as angstrom(A^0). I don't understand how I get this.Please help me. Thanks.

[Edit by Jochen Arndt: Added code formatting]

Posted 3-Jun-15 21:32pm

Member 11735960

Updated 3-Jun-15 21:44pm

Jochen Arndt

v2

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CPallini 4-Jun-15 4:24am

I suggest you reading a tutorial on C arrays, see, for instance:
http://www.cplusplus.com/doc/tutorial/arrays/

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Jochen Arndt · Answer 1 · 2015-06-03T21:42:00

If you want to print a string you must use the printf format character for strings which is '%s' and pass the pointer to the string:

C++

printf("%s",a);

You are printing a single character which is nor part of your string a:

C++

a[0] = 'l';
a[1] = 'k';
a[2] = 0; // The NULL termination character
//a[3] = ? Undefined because this is out of bound

Raul Iloc · Answer 2 · 2015-06-03T21:44:00

Solution 2

Your char table has length of 3, and you are trying to access value outside the array boundary. The valid indexes are 0, 1, and 2, but because you are using char array the last value a[2] is used to store the end of string (NULL value).

Posted 3-Jun-15 21:44pm

Raul Iloc