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Posted 5 Nov 2010

# A simple program to solve quadratic equations with

, 10 Nov 2010 CPOL
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The correct way to solve quadratic equations is none of the above. For the correct algorithm as applied in the following function, seenumerical recipes in C and the Wolfram site at http://mathworld.wolfram.com/QuadraticEquation.html#include bool quadratic(double a, double b,...
The correct way to solve quadratic equations is none of the above. For the correct algorithm as applied in the following function, see
numerical recipes in C and the Wolfram site at http://mathworld.wolfram.com/QuadraticEquation.html

```#include <limits>
bool quadratic(double a, double b, double c, double& x1, double& x2, double y, double z)
{
double delta=0.0e+00, q=0.0e+00, bsign, y1, y2;
const double eps = std::numeric_limits()<double>.epsilon();
// equation is: a*x^2 + b*x + c = 0; a cannot be zero.
if ( fabs(a) <= eps ) { return false; }

delta=b*b-4.0*a*c;
if ( delta<0.0e+00 ) { return false; }
if ( delta>=0.0e+00 && delta <= eps )
{ x1=(-1.0*b/(2.0*a)); x2=x1; return true; }

bsign=1.0e+00;
if ( fabs(b)>1.0e-16 )  { bsign=b/fabs(b); }
else { if ( b<0.0e+00 ) { bsign=-1.0e+00; } }

q=(-0.5)*(b+bsign*sqrt(delta));

// the roots of the equation are:
y1=q/a; y2=c/q;

// find if any of the roots is in the given [y,z] interval
if (( y<=y1 )&&( y1<=z ))
{
x1=y1; x2=y2;
}
else if (( y<=y2 )&&( y2<=z ))
{
x1=y2; x2=y1;
}
else
{
x1=y1; x2=y2;
}

return true;
}```

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 Software Developer (Senior) Italy
Senior Software Developer in C/C++ and Oracle.
Ex-physicist holding a Ph.D. on x-ray lasers.

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