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I want to insert only one row in a table in SQL server 2008 using C# ADO.Net...
If any user want to insert another row in that table then it is not possible message should be display....
Please Just reply the Query & CODE....
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Why have you repeated this question a third time?
One of these days I'm going to think of a really clever signature.
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M.T.H.Danish wrote: If any user want to insert another row in that table then it is not possible message should be display....
Please Just reply the Query & CODE....
A database does not display messages, it holds data. It holds data in bulk, not in "single records". What you want does not make much sense from a data-viewpoint.
Now, this is not the place to "order" code like you do. The questions on the forums are answered by volunteers, in their free time. Put it in a object, serialize it, and stuff it in a single-column blob.
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I want to insert only one row in a table in SQL server 2008 using C# ADO.Net...
If any user want to insert another row in that table then it is not possible message should be display....
Please Just reply the Query & CODE....
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M.T.H.Danish wrote: If any user want to insert another row in that table then it is not possible message should be display
Take a look at locking a table:
http://manuals.sybase.com/onlinebooks/group-as/asg1250e/sqlug/@Generic__BookTextView/55452[^]
M.T.H.Danish wrote: Please Just reply the Query & CODE
I didn't downvote you, but I think most people here won't like to do your work. You can ask questions, you can show your code and ask for help, but you have to do your work on your own. So my answer is:
Definitely not!
------------------------------
Author of Primary ROleplaying SysTem
How do I take my coffee? Black as midnight on a moonless night.
War doesn't determine who's right. War determines who's left.
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I want to create a table in which only one row should be insert.
If any user want to insert another row in that table then it is not possible...
Please just reply query...
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Try using something like:
select count(*) from MyTable
if (count = 0) then
do insert
else
fail
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Why would you need a table with just 1 row?
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Try an INSTEAD OF TRIGGER
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Make sure the Primary Key can only contain 1 value using a check constraint:
ALTER TABLE [dbo].[MyTable] WITH CHECK ADD CONSTRAINT [CK_OneRow] CHECK (([Id]=(1)))
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Michael Potter wrote: Make sure the Primary Key can only contain 1 value using a check constraint:
ALTER TABLE [dbo].[MyTable] WITH CHECK ADD CONSTRAINT [CK_OneRow] CHECK (([Id]=(1)))
That is a very cool way to solve a very strange request. I'll give it a 5.
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Super solution but can't be replicated in other databases like oracle.
Identity is a near equivalent to rowid concept in Oracle but its a dynamic value i.e not a sequence generator . Hence may be Only possible in sql server.
Regards
Sreeni
www.sreenivaskandakuru.com
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If you change the start value of the identity seed (I'm pretty sure this can be done) and truncate the table the hard coded 1 would fail  mind you it is a silly request in the first place and I suspect the OP does not even know what you are talking about.
Never underestimate the power of human stupidity
RAH
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It may not be as useless as it first appears. I have used this method to hold global variables that are used by more than one application.
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It'd be easier to create a view and be done with it;
CREATE VIEW GlobalSettingsTable AS
SELECT 1 AS ColumnName,
2 AS Nanana,
'C:\Program Files'
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Yes - if your values are constants.
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No, also for dynamic values; you can put sub-selects in there, or even calls to managed code 
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Don't get me wrong, I did not consider it useless (even in this idiotic context) just being a pedantic bastard.
Never underestimate the power of human stupidity
RAH
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Hi All,
Thanks in advance..
I have an application that gets installed perfectly fine without hasles in win XP etc. and gets connected to the DB.
When I install the application in Win 7, It gets installed fine but gives an exception as mentioned below when tried to connect to the Access Database.
Exception Message: Provider cannot be found.
it may not be properly installed.
Inner Exception: at ADODB.ConnectionClass.Open(String ConnectionString, String UserID, String Password, Int32 Options)
at VersesOnArt.Startup.LinkTables()
Please help me to get out of error. VERY VERY URGENT..
Thank you once again,
Kuchimanchi
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rskuchimanchi wrote: it may not be properly installed.
Is ADO installed? The 32 or the 64-bit version?
rskuchimanchi wrote: VERY VERY URGENT..
No, it ain't. In fact, I'm gonna ignore the rest of the thread.
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Hi,
Not sure it is the right forum...
I'm using VisualStudio 2010 and trying to use schema compare tool to deploy changes from my db project to my database (SQL server 2008).
when trying to deploy the changes I made in my db project I get anexception with the following message:
"Cannot create index. Object 'v_TQ_IFCR_DATA_COVERAGE' was created with the following SET options off: 'ANSI_NULLS, QUOTED_IDENTIFIER'."
If I will go the the index properties,I see that AnsiNulls
and QuatedIdentifiers are set to project default.
When changing those settings to ON I manage to deploy all updates without any exception.
How can I change project default settings?
I have more then 200 different objects(tables,stored procedures,functions,indexes etc.) and I don't want to change the settings of each object.
Anyone?
Thanks,
Eli
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problem solved.
In my schema compare the options if "Ignore AnsiNulls" and
"Ignore QuatedIdentifiers" where checked,so updated AnsiNulls and QuatedIdentifiers settings was not marked as needs to be updated during the schema compare.
Also,I've set AnsiNulls and QuatedIdentifiers default settings
to true in database.sqlsettings file.
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hi all
im trying to export table loan to excel file but i get this error in sql 2008 r2
Msg 7308, Level 16, State 1, Line 2
OLE DB provider 'Microsoft.Jet.OLEDB.4.0' cannot be used for distributed queries because the provider is configured to run in single-threaded apartment mode.
my query is
insert into OPENROWSET('Microsoft.Jet.OLEDB.4.0',
'Excel 8.0;Database=D:\testing.xls;',
'SELECT * FROM [Bankmellat$]') select * from BML.Loan
anyone can help me for fix this problem
thanks regards
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i do your solution but i get error and my problem is stable and i get error again.
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