adding option to list using jquery

Question

1.00/5 (1 vote)

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JavaScript

var list =["haider","faisal","adnan","kami","asad"]
var handles  = list.sort();
var options = '';
        for (var i = 0; i < handles.length; i ++) {
            options += '<option value="' + handles[i] + '">' + handles[i] + '</option>';
        }
        $('#listBox').html(options);

now i want to insert "faizan" and the list order is maintained any idea how to do it?

Posted 23-Jun-12 5:07am

agha_ali22

Updated 23-Jun-12 19:59pm

v8

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Comments

Sergey Alexandrovich Kryukov 23-Jun-12 16:27pm

What do you mean "maintained"? If you mean alphanumeric order, it is already not maintained, even before Asad is added...
--SA

agha_ali22 24-Jun-12 1:46am

var handles = list.sort() is sorting the array

3 solutions

Solution 1

JavaScript

$('#listBox').append("<option value="faizan">faizan</option>");

Posted 23-Jun-12 10:02am

mhamad zarif

Comments

agha_ali22 24-Jun-12 1:47am

it will append the faizan in the last i want to append without disturbing its order

mhamad zarif 24-Jun-12 5:04am

Do u mean that u want to insert it at the beginning ?

agha_ali22 24-Jun-12 7:50am

see my solution

Solution 6

just write this after your code
$("#listBox").sortable('refresh');

Posted 6-Jul-12 23:35pm

rizwan muhammed khan gouri

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Ahmed Ibrahim Assaf · Accepted Answer · 2012-06-24T22:39:00

El-salmo 3likom wa ra7mat ALLAH we Barakatoh,

Dear,

another Solution:
you can add "faizan" to the list

JavaScript

var list =["haider","faisal","adnan","kami","asad"]
function addOption(Obj)
{
//clear list
$('#listBox').html("");
//add new option
list.push(Obj);
//sort the array
var handles  = list.sort();
var options = '';
        for (var i = 0; i < handles.length; i ++) {
         options += '<option value="' + handles[i] + '">' + handles[i] + '</option>';
        }
        $('#listBox').html(options);

all you have to do :
call the function --> addOption("faizan");

Best Regards:
Ahmed Assaf
eBusiness Developer

adding option to list using jquery

3 solutions

Solution 3

Solution 1

Solution 6

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