How to convert a date time object to a countable variable

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PHP

$Jahr = date('Y');
$zahl = date('n');
if (isset($_GET['vor']))
	{
	echo $datum = hallo;
	echo $zahl = $zahl ++;
	}
	else
		{
		if (isset($_GET['zurück']))
			{
			echo $datum = hallo2;
			}
			else
				{
				echo $datum = $monate[$monat]. " ". $Jahr;
				}
	}

now $zahl is always 8 (month august). I think I have to convert it to a string for count

Posted 11-Aug-12 6:54am

Chi Ller

Updated 12-Aug-12 5:05am

v2

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Comments

helmi77 11-Aug-12 13:43pm

What exactly are you trying to achieve and where's the problem?

Chi Ller 11-Aug-12 14:17pm

it´s part of a calendar. i try to change the month on the display

Mohibur Rashid 11-Aug-12 13:45pm

Your question does not make sense. $zahl is already integer, how counting would help if you convert to string?

Chi Ller 11-Aug-12 14:16pm

but it doesn´t count. so what should i do?

Volynsky Alex 11-Aug-12 15:08pm

Please see following articles:
http://ca3.php.net/manual/en/function.date.php
http://stackoverflow.com/questions/10569053/convert-datetime-to-string
http://af-design.com/blog/2010/03/13/microsoft-sql-server-driver-for-php-returns-datetime-object/

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Volynsky Alex · Answer 1 · 2012-08-11T09:08:00

Solution 1

Try it:

PHP

echo date(  "F j, Y, g:i a", strtotime( $datetime_value ) );

Posted 11-Aug-12 9:08am

Volynsky Alex

Comments

Chi Ller 11-Aug-12 15:52pm

Doesn´t work... the number is now 1 and doesn´t change its value