Need help with a code

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ProcessStartInfo startInfo = new ProcessStartInfo();

startInfo.FileName = @"c:\windows\system32\rundll32.exe";

startInfo.Arguments =
@"C:\WINDOWS\System32\shimgvw.dll,ImageView_Fullscreen C:\Users\Sony\Desktop\c.jpg"

I want to specify the image URI (C:\Users\Sony\Desktop\c.jpg)as a string variable.So what changes do I have to make in startInfo.Arguments.

Posted 11-Apr-13 23:02pm

Member 9805113

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Thomas Daniels · Answer 1 · 2013-04-11T23:04:00

Solution 1

Hi,

Try this:

C#

startInfo.Arguments =
@"C:\WINDOWS\System32\shimgvw.dll,ImageView_Fullscreen \"" + filenameStringVariable + "\""; // change 'filenameStringVariable' into the name of your string variable

Hope this helps.

[EDIT #2]String surrounded with quotes, as Steve44 recommended.[/EDIT]
[EDIT]

If you want to open a photo in a photo viewer, then you can try this:

C#

ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = filenameStringVariable;
Process.Start(startInfo);

This code opens the file with the default application of the file. If the file is a picture, then a picture viewer will open the picture.

Posted 11-Apr-13 23:04pm

Thomas Daniels

Updated 11-Apr-13 23:40pm

v3

Comments

Member 9805113 12-Apr-13 5:15am

I have tried that but the photo viewer itself doesn't open.

Thomas Daniels 12-Apr-13 5:28am

I updated my answer.

Steve44 12-Apr-13 5:30am

Does it work in your static sample above?
Does your file path or name contain spaces? In this case you would have to surround the string with quotes within the string:
@"C:\WINDOWS\System32\shimgvw.dll,ImageView_Fullscreen \"" + filenameStringVariable "\"";
This is recommended in general.

Member 9805113 12-Apr-13 6:05am

No.I dont have spaces in file path. The process starts and closes immediately.It does not open through photo viewer and image does not get displayed.

Pro Idiot · Answer 2 · 2013-04-12T01:53:00

C#

static void OpenImage()
        {
            //string path = @"C:\Users\Desktop\Skype_Files\abc.jpg";
            //System.Diagnostics.Process.Start(path);


            string Path = @"C:\Users\Desktop\Skype_Files\abc.jpg";
            Process p = new Process();
            p.StartInfo.FileName = "rundll32.exe";
            //Arguments
            p.StartInfo.Arguments = @"C:\WINDOWS\System32\shimgvw.dll,ImageView_Fullscreen " + Path;

            p.Start();
        }

You can change the value of the variable "Path" and it the picture will be opened in the image viewer.

Hope it helps

[ Happy Coding ]