How to wap in C to read a number until -1 is encountered and count how many even and odd number entered by user?

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in C programming ,control statements chapter.

What I have tried:

C++

/*I have done*/
int num,even=0,odd=0;

do{printf("enter number")
scanf("%d",&num);
if(num÷2==0)
even+=1;
else odd+=1;
printf("even number %d",even);
printf("odd number %d",odd);

Posted 20-Mar-18 5:26am

Deepak pandey

Updated 20-Mar-18 6:12am

KarstenK

v2

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Deepak pandey 20-Mar-18 11:25am

This is just a logic is it correct ??

4 solutions

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Patrice T · Accepted Answer · 2018-03-20T06:06:00

Learn to indent properly your code, it show its structure and it helps reading and understanding. It also helps spotting structures mistakes.

C++

/*I have done*/
int num,even=0,odd=0;
do{
  printf("enter number")  // ; is missing here
  scanf("%d",&num);
  if(num÷2==0)
    even+=1;
  else 
    odd+=1;
// } is missing here
// end of loop is missing here
printf("even number %d",even);
printf("odd number %d",odd);

Professional programmer's editors have this feature and others ones such as parenthesis matching and syntax highlighting.
Notepad++ Home[^]
ultraedit[^]

Note that your code will count -1 as an input value.

Doug Joseph · Accepted Answer · 2018-03-20T06:13:00

Solution 4

This should do the trick:

C++

int num = 0, even = 0, odd = 0;

do
{
    printf( "enter number (-1 exits):" );
    scanf( "%d", &num );
    if ( num != -1 )
    {    
        if ( num & 0x01 ) odd++;
        else              even++;
    };
    
} while ( num != -1 );
    
printf( "even number %d", even );
printf( "odd number %d",  odd );

I Hope that helps you.
-Doug

Posted 20-Mar-18 6:13am

Doug Joseph

v2

Comments

W∴ Balboos, GHB 20-Mar-18 13:08pm

Your answer's close enough to mine that I won't submit one. Here's the change.

int counter[2];

Then, for all numbers you could simply have:

counter[num&0x01]++;

Just a nuance, but I thought you might find it interesting.

Doug Joseph 20-Mar-18 14:06pm

Dude... great call! I like that even better. :)

KarstenK 21-Mar-18 4:32am

You should do his homework. He should learn coding. ;-)

KarstenK · Accepted Answer · 2018-03-20T05:32:00

Solution 1

At first you need some tutorial about the do-while loop.

The resulting code could look like this:

C++

int count = 0;
do {
count++;
if( ... )
  break;//quick leave loop
}while( num!= -1;

Posted 20-Mar-18 5:32am

KarstenK

Dezhi Zhao · Accepted Answer · 2018-03-20T05:37:00

Solution 2

Just change

num÷2==0

to

num%2==0

, then you'll be good.

Posted 20-Mar-18 5:37am

Dezhi Zhao

Updated 20-Mar-18 5:39am

v2