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I don't understand the meaning of this error message.
why do I get this error? here is the coding;

#include <iostream>
using namespace std;


int f(int &x, int c);

int main()
{
cout <<" testing reference"<<f(5,5);

return 0;
}


int f(int &x, int c) {
c = c - 1;
if (c == 0) return 1;
x = x + 1;
return f(x, c) * x;
}
Posted

1 solution

You are passing first argument as reference. It means that the actual argument should be an object that can be referenced, it can not be an immediate constant such as 5. Passing by reference allows the function modify the value of this argument, so it should be a variable.

You should either remove '&' from the function signature, or use a variable to pass as the first argument.

—SA
   
v2
Comments
David A. Gray 29-Jun-15 12:53pm
   
Equally important is that if the argument is a reference, you must pass by reference as well, using the address of operator (&).

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