how to take time difference between these two

Question

4.00/5 (1 vote)

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i have one table like this

starting time ending time
16:26:46:235 16:26:50:924

i want time difference..

please help me out

Posted 1-Sep-15 1:01am

Member 11337367

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Herman<T>.Instance 1-Sep-15 7:56am

Timediff in seconds?
See DateDiff here

CHill60 1-Sep-15 8:00am

As per your earlier comment to me - that's the answer!

Herman<T>.Instance 1-Sep-15 8:28am

done

Maciej Los 1-Sep-15 8:06am

What have you tried? Where are you stuck?

3 solutions

Solution 3

Timediff in seconds?
See DateDiff here

Posted 1-Sep-15 2:31am

Herman<T>.Instance

v3

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Magic Wonder · Accepted Answer · 2015-09-01T02:14:00

Hi,

Check this...Sql time difference between two dates result in hhmmss[^]

...with little modifications

SQL

declare @StartDate time, @EndDate time

select @StartDate = '16:26:46:235&',@EndDate='16:26:50:924';

SELECT CONVERT(VARCHAR(12), DATEADD(MS, DATEDIFF(MS, @StartDate, @EndDate), 0), 114) AS TimeDiff

Hope this will help you.

Cheers

arindamrudra · Accepted Answer · 2015-09-01T02:15:00

Try the below code:

SQL

SELECT  CAST(DATEDIFF(HOUR, '16:26:46:235', '16:26:50:924') AS VARCHAR)
         + ':' + CAST(DATEDIFF(MINUTE, '16:26:46:235', '16:26:50:924') AS VARCHAR)
         + ':' + CAST(DATEDIFF(SECOND, '16:26:46:235', '16:26:50:924') AS VARCHAR)
         + ':' + CAST(DATEDIFF(MILLISECOND, '16:26:46:235', '16:26:50:924') AS VARCHAR)

This should give you what you are looking for.

how to take time difference between these two

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