How to convert XML to string format in C#

Question

1.00/5 (1 vote)

See more:

<language>
<record lang=".net">
<record lang="java">
<record lang="php">

i want to the ouput on string temp=".net,java,php"

What I have tried:

<language>
<record lang=".net">
<record lang="java">
<record lang="php">

i want to the ouput on string temp=".net,java,php". i tried to bind it, but not able to come. can anyone pls help me.

Posted 28-Aug-17 1:29am

IsaiSelvan

Updated 28-Aug-17 2:16am

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Thomas Daniels · Accepted Answer · 2017-08-28T02:16:00

That XML isn't valid because there are no closing tags, but assuming your actual XML is valid, you can do this:

C#

using System.Xml.Linq;

C#

string xml = @"<language>
<record lang="".net""></record>
<record lang=""java""></record>
<record lang=""php""></record>
</language>";
string temp = string.Join(",", XDocument.Parse(xml).Root.Elements().Select(x => x.Attribute(XName.Get("lang")).Value));

XDocument.Parse parses your string into an XDocument
.Root takes the root element, <language>
.Elements() takes the child elements, the three <record>-tags.
.Select(x => x.Attribute(XName.Get("lang")).Value) takes the value of the "lang" attribute for each of these elements. The result is an IEnumerable<string>.
string.Join concatenates these strings, with a comma as separator.