Cannot convert to string

Question

1.00/5 (1 vote)

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Hi Got this class

C#

class Normale : IMathOperationDemo
    {
        decimal Alpha;
        decimal Beta;
        string mesatarja;
        string moda;
        string mesorja;
        string varianca;
        string Minimum;
        string Maximum;
        public string getMinimum(string Minimum)
    {
    Minimum.Value = Alpha.Value.ToString();
    return Minimum;
    }
        public string getMaximum(string Maximum)
        {
            Maximum.Value = Beta.Value.ToString();
            return Maximum;
        }
        public string GetMesatarja(string mesatarja)
        {
            mesatarja = (Alpha + Beta) / 2;
            return mesatarja.ToString
                                }
        public string GetMesorja(string mesorja)
        {
            mesorja = (Alpha + Beta) / 2;
            return mesorja.ToString;
        }
        public string GetModa(string moda)
        {
            moda = (Alpha + Beta) / 2;
            return moda.ToString;
        }
        public string GetVarianca(string varianca)
        {
            varianca = ((Beta-Alpha+1)*(Beta-Alpha+1)-1) / 12;
            return varianca.ToString;
        }
    }
}

Got errors :

'string' does not contain a definition for 'Value' and no extension method 'Value' accepting a first argument of type 'string' could be found (are you missing a using directive or an assembly reference?

Cannot implicitly convert type 'decimal' to 'string'

What's wrong?

Please help

Regards

Posted 8-Jun-11 6:31am

KORCARI

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4 solutions

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Monjurul Habib · Answer 1 · 2011-06-08T08:54:00

Solution 3

C#

public string GetMesatarja(string mesatarja)
{
    mesatarja =Convert.ToString((Alpha + Beta) / 2);
    return mesatarja;
}
public string GetMesorja(string mesorja)
{
    mesorja = Convert.ToString((Alpha + Beta) / 2);
    return mesorja;
}
public string GetModa(string moda)
{
    moda = Convert.ToString((Alpha + Beta) / 2);
    return moda;
}
public string GetVarianca(string varianca)
{
    varianca = Convert.ToString(((Beta-Alpha+1)*(Beta-Alpha+1)-1) / 12);
    return varianca;
}

Posted 8-Jun-11 8:54am

Monjurul Habib

Comments

Sergey Alexandrovich Kryukov 8-Jun-11 15:43pm

Monjurul, can you see how useless all this is? How can it help OP? Whole thing makes no sense at all, and you cannot add any sense by fixing it.
Please see my answer.
--SA

Monjurul Habib 8-Jun-11 16:29pm

yes that is the answer.

KORCARI 8-Jun-11 17:04pm

SAKryukov thx anyway man. I don't get it why you become so upset but sorry. Just trying to learn from the more experienced ones

Sergey Alexandrovich Kryukov 8-Jun-11 18:06pm

I'm not upset, I'm just sorry for you. I'm only upset that I cannot help you. You repeat the same function several time and probably cannot even see it. Please, for your own save, wake up and think thoroughly what are you doing.
--SA

KORCARI 9-Jun-11 2:38am

I am not repeating it it is just some demo.
For me in this moment the most important is to extract from method to textbox even if inside methods is only a subtractions or add operations A+ B.
My second part of job is to realize some statistical distribution functions but this is my homework and I got to do it myself.
Anyway thx for the time spent over my posts
Regards

Sergey Alexandrovich Kryukov · Answer 2 · 2011-06-08T09:41:00

Whole thing is such a bad idea. You're trying to convert all calculations to string. This is pointless.
Again you certainly still have a big confusion on what is programming for.

Did you pay attention that Mesatarja, GetMesorja and Moda is the same very function under different names. Do you think that different names of arguments may make any difference.

I feel you misunderstood the very basics of elementary programming. You probably don't understand what a method, argument, variable do.
I don't know how to help here. You need to start with elementary course on programming and do very simple exercises to see how it works.

—SA

wizardzz · Answer 3 · 2011-06-08T06:36:00

Solution 1

You are using ToString instead of ToString() I noticed.
Also in the steps where you are doing math, you should wrap with ToString().
For example:

C#

public string GetVarianca(string varianca)
{
    varianca = ((Beta-Alpha+1)*(Beta-Alpha+1)-1) / 12;
    return varianca.ToString;
}

will not work, but this will:

C#

public string GetVarianca(string varianca)
{
    return (((Beta-Alpha+1)*(Beta-Alpha+1)-1) / 12).ToString(); 
}

Because you are implicitly converting the results of a math function to a string "varianca"
You should probably check that the result won't throw an Exception, too. This is just to get you started.

Posted 8-Jun-11 6:36am

wizardzz

Updated 8-Jun-11 6:37am

v2

Comments

Sergey Alexandrovich Kryukov 8-Jun-11 15:44pm

Can you see how useless all this is? How can it help OP? Whole thing makes no sense at all, and you cannot add any sense by fixing it. You can only prolong the illusion that OP is programming something.
Please see my answer.
--SA

wizardzz 8-Jun-11 15:48pm

I saw your answer, and it is more of a comment in my opinion. I could easily tear apart the OP every time I see a bad question from a beginner, but I wouldn't call it an answer.

Monjurul Habib 8-Jun-11 16:28pm

We should consider as an answer.Because a programmer should learn the basic concepts of programming first.Beginner can not be an excuse.

wizardzz 8-Jun-11 16:29pm

I'll start trying this approach on novice QA's in the future, though from my experience it will bring out some univoters.

Monjurul Habib 8-Jun-11 16:32pm

apologize, i think you misunderstood me.Experts should help beginners but not with their wrong approach.

Sergey Alexandrovich Kryukov 8-Jun-11 18:13pm

I'm not sure I understand you correctly, but here is what I think: sometimes a correct answer makes much more harm than not answering at all. If we give an answer wich helps to continue development in a wrong approach, for example. I'm trying to never miss a chance to point out bigger problem. As to this case, I'm very sorry for OP, actually -- it all leads nowhere. What to do to help? If I just ignore the bigger problem, it will get worse, but later. I'm really trying to help, not to answer the question...
--SA

Monjurul Habib 8-Jun-11 18:22pm

yes i am completely agree with you.

Sergey Alexandrovich Kryukov 8-Jun-11 18:09pm

Same with me; and I expect furious response and down votes, I do get a lot of down-votes but simply ignore it.
--SA

Sergey Alexandrovich Kryukov 8-Jun-11 18:07pm

Of course not and of course you're right. I don't think I can answer and I don't think any answer can help, including yours, honestly.
I just don't know how else to help.
--SA

Monjurul Habib 8-Jun-11 18:25pm

yes i realized but later.

KORCARI 8-Jun-11 17:03pm

SAKryukov thx anyway man.
I don't get it why you become so upset but sorry.
Just trying to learn from the more experienced ones

aidin Tajadod · Answer 4 · 2011-06-08T06:39:00

In this code:

public string getMinimum(string Minimum)
  {
  Minimum.Value = Alpha.Value.ToString();
  return Minimum;
  }

Minimum is string. you can not use Minimum.value=.... .

public string getMinimum(string Minimum)
  {
   return Alpha.ToString();
  }

Do the same for others.

the second problem is

public string GetMesatarja(string mesatarja)
        {
            mesatarja = (Alpha + Beta) / 2;
            return mesatarja.ToString
                                }

change it to

public string GetMesatarja(string mesatarja)
    {
        mesatarja = ((Alpha + Beta) / 2).ToString();
        return mesatarja;
                            }

and do the same for others.