how to remove repeted number in that array...

One way (probably not the most efficient, but it works) would be to create a new array and expand it as you add numbers. Every time you add something new, check to make sure it doesn't already exist in the new array.

There's some easy obvious optimizing you can do (and other tricks to make that faster), for example allocate the array's size some number of integers at a time (say 10) instead of reallocating every single instance and only reallocate when you're about to exceed that size. At the end, trim the excess memory with a realloc call.

There's probably other faster methods but that comes to mind off the back.

int RemoveRep(int array[], int n)
　　{
　　int *arrayflag = (int *)malloc(n*sizeof(int));
　　int left = 0, i = 0;
　　while(i　　arrayflag[i++] = false; //初始化标志数组
　　for(i=0;i　　{
　　arrayflag[array[i]] = array[i]; //将出现过的数保存到对应的位置
　　}
　　for(i=0;i　　{
　　if(arrayflag[i] != false)
　　array[left++] = arrayflag[i];
　　}
　　return left;
　　}