selecting needed column in data table with linq

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There are many columns in data table .
But i want to need three column .
I want to know how to write to get only needed column with linq .

Posted 31-Jan-12 3:48am

rosyBurmese

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bbirajdar · Answer 1 · 2012-01-31T03:50:00

Solution 1

Use this

C#

var selectedColumn =dtDataTable.AsEnumerable().Select(s=>s.Field<string>("ColumnName"));

Posted 31-Jan-12 3:50am

bbirajdar

Updated 31-Jan-12 20:27pm

v2

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) · Answer 2 · 2012-01-31T04:02:00

Solution 2

Try this....

C#

var selectedColumn =  from m in MyTable
                      where ....
                      select new
                      {
                          m.firstColumn,
                          m.secondColumn,
                          m.thirdColumn
                      };

Just write as many columns you want inside "select new {}".....

Posted 31-Jan-12 4:02am

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ)

Comments

bbirajdar 1-Feb-12 2:26am

This code gives the error as :

Error 1 Could not find an implementation of the query pattern for source type 'System.Data.DataTable'. 'Where' not found.

Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) 1-Feb-12 7:05am

After "where", I have put .... That means you should put the appropriate where condition. Anyway just post the exact code what you implemented in your code.

bbirajdar 1-Feb-12 8:58am

The error is not for ... Its for 'MyTable'. The DataTable has to implement 'IEnumerable' interface so that LINQ can be fired on it..

The change should be ...
var selectedColumn = from m in MyTable.AsEnumarable()
where ....
select new
{
m.firstColumn,
m.secondColumn,
m.thirdColumn
};