How to find alphanumeric word from a string using regular expression?

Question

1.00/5 (1 vote)

See more:

Get 20% Off Your Entire Order & FREE Shipping (first time customers only)! Enter coupon code NEW20VISION at checkout. Limited time offer.

Quote:
I am getting this type of string from db.I have to find out if there is any alphanumeric word in the string.If it contains any alphanumeric word.I have underline it.Like in the above case it is:NEW20VISION

Posted 14-May-12 1:40am

Tirthankar Dutta

Updated 28-Aug-18 1:14am

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Comments

Sandeep Mewara 14-May-12 8:04am

Ok. And what have you tried so far?

Tirthankar Dutta 14-May-12 8:06am

I have tried the regex like @"^[a-zA-Z0-9]\s*$";

VJ Reddy 23-May-12 6:08am

Thank you for accepting the solution :)

2 solutions

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RDBurmon · Accepted Answer · 2012-05-14T02:05:00

Solution 1

Try this

C#

string s = TextBox1.Text;
string str = "";
string[] words = s.Split(' ');
foreach (string word in words)
{
    Regex r = new Regex("[a-zA-Z]");

    if (r.IsMatch(word))
    {
        Regex r1 = new Regex("[0-9]");
        if (r1.IsMatch(word))
        {
          str=str +  " " + "<U>" +  word + "</U>";
        }
        else
            str=str +  " " + "" +  word + "";
    }
    else
            str=str +  " " + "" +  word + "";
}

Label1.Text=str;

Hope this helps if yes then accept and vote the answer otherwise revert back with your queries.
--RDBurmon Sr.Software Engineer

Posted 14-May-12 2:05am

RDBurmon

Comments

Rahul Rajat Singh 14-May-12 8:08am

I am no expert on regex but it seems like the first if condition will fail for the required words we want and all the logic to find them is inside that condition only. I might be wrong, please correct me if I am.

Rahul Rajat Singh 14-May-12 8:15am

I was wrong. the solution is perfect. I tried this one and it worked fine. +5 from me.

static void Main(string[] args)
{
string s = @"Get 20% Off Your Entire Order & FREE Shipping (first time customers only)! Enter coupon code NEW20VISION at checkout. Limited time offer. ";
string str = "";
string[] words = s.Split(' ');
ArrayList foundWords = new ArrayList();

foreach (string word in words)
{
Regex r = new Regex("[a-zA-Z]");

if (r.IsMatch(word))
{
Regex r1 = new Regex("[0-9]");
if (r1.IsMatch(word))
{
foundWords.Add(word);
}
}
}

foreach (string strr in foundWords)
{
Console.WriteLine(strr);
}
}

RDBurmon 14-May-12 8:17am

Thanks
Tirthankar-Dutta : Try above code and let us know .

Tirthankar Dutta 14-May-12 8:18am

Thanks all.It worked

VJ Reddy 14-May-12 11:24am

Good answer. 5!

Maciej Los 14-May-12 15:35pm

To find all words containing numbers, correct pattern is: \w*([0-9]+)\w*

VJ Reddy · Accepted Answer · 2012-05-14T05:23:00

The Solution 1 given by RDBurmon is good.

As an alternative the following regular expression can be used to search for the alpha numeric words. It first searches for a word with 2 or more alpha numeric characters, then it checks whether at least one digit and at least one character is present in the searched word and only if it is so, the word will be captured as a group.

Further the captured group can be used for replacement. For eg. each of the captured word can be enclosed within <u> and </u> as shown below:

The Regular Expression can be tested here http://regexhero.net/tester/[^]

C#

string inputText = @"Get 20% Off Your Entire Order & FREE Shipping " +
       @"(first time customers only)! Enter coupon code NEW20VISION at checkout." +
       @"Limited time offer. NEW20 20VISION  New20New20New20Ne20  N2";

MatchCollection alphaNumMatches = Regex.Matches(inputText,
       @"(?=\w{2,})(?=\w*\d+)(?=\w*\p{L}+)(\w{2,})",
       RegexOptions.CultureInvariant | RegexOptions.IgnoreCase);

foreach(Match match in alphaNumMatches){
    if (match.Groups.Count > 0)
        Console.WriteLine (match.Groups[1].Value);
}

string replacedText = Regex.Replace(inputText,
       @"(?=\w{2,})(?=\w*\d+)(?=\w*\p{L}+)(\w{2,})",
       @"<u>$1</u>");

Console.WriteLine (replacedText);

//Output

//NEW20VISION
//NEW20
//20VISION
//New20New20New20Ne20
//N2
//Get 20% Off Your Entire Order & FREE Shipping (first time customers only)! Enter coupon code <u>NEW20VISION</u> at checkout.Limited time offer. <u>NEW20</u> <u>20VISION</u>  <u>New20New20New20Ne20</u>  <u>N2</u>