having a decimal dynamic value which dynamically i want to display the last 2 digits of the decimal value such as 0.12289 and 1.23564875 want to display 0.89 and 1.75

Question

0.00/5 (No votes)

See more:

Dear All,

having a decimal dynamic value, which dynamically i want to display the last 2 digits of the decimal value such as 0.12289 and 1.23564875 and so on. want to display 0.89 and 1.75

Long life for Code Project Members.

Thanks in advance.

Posted 22-May-12 1:46am

acceptProblem

Add a Solution

6 solutions

Solution 5

An alternative using Regex is as follows:

C#

double num = 1.23564875;
string numString = Regex.Replace(num.ToString("R"),@"(?<=\d*\.)\d*(?=\d{2})","");
Console.WriteLine (numString);

//Output
//1.75

Posted 22-May-12 2:42am

VJ Reddy

Comments

Shahin Khorshidnia 27-May-12 13:02pm

Good solution. My + FIVE

VJ Reddy 30-May-12 7:47am

Thank you, Shahin :)

Solution 2

Try this:

C#

string s = "0.12289";
string[] words = s.Split(".");
string result=words[0]+"."+words[1].Substring (words[1].Length-2);

Posted 22-May-12 1:58am

deeptibansal

Solution 3

Dirty, but working for both of your test cases:

C#

double d = 0.12289;
string ds = d.ToString("R", System.Globalization.CultureInfo.InvariantCulture);
int s = (ds.IndexOf(".") + 1);
int l = ((ds.Length) - s);
string sout = ds.Substring(0, s) + ds.Substring(s+l-2, 2);
MessageBox.Show(sout);

Posted 22-May-12 1:58am

JF2015

Solution 6

call the function getamount for your problem it will return your desired result

C#

protected void Page_Load(object sender, EventArgs e)
    {
        double dec1 = 1.23564875;
        TextBox1.Text = GetAmount(dec1);
    }

private string GetAmount(double amount)
    {
        string[] str = amount.ToString().Split('.');

        string str1 = str[0];
        string str2 = str[1];
        string str3 = str2.Substring(str2.Length - 2);
        return str1 + "." + str3;

    }

Posted 23-May-12 2:28am

Prosan

Updated 23-May-12 2:32am

v2

Solution 1

Consider using Math.Round[^]

Posted 22-May-12 1:57am

AhsanS

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

acceptProblem · Accepted Answer · 2012-05-27T00:50:00

Solution 7

Thanks from all of you guys.
i solve my problem in the following way.it works well.

C#

double _val = 0.12121219;
            textBox1.Text = _val.ToString("0.##");

Posted 27-May-12 0:50am

acceptProblem