change the position of xml every 5 mins

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Hi
I have a xml file in which i have 5 blocks totally and i want to change the position simutaneously (i.e) The first element after a period of time should be displayed last and vice versa how to do it

Posted 30-Sep-12 22:39pm

Shashwath7

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Rock (Multithreaded) 1-Oct-12 4:44am

I think your question is not clear...

Shashwath7 1-Oct-12 4:50am

consider the xml format
<rows>
<img>sample1.gif</img>

<rows>
<img>sample2.gif</img>

<rows>
<img>sample3.gif</img>

<rows>
<img>sample4.gif</img>

<rows>
<img>sample5.gif</img>

these 5 tags shoul get changed in position dynamically
for example img tag in 1st position to 5th and 2nd to 4th etc and it has to be like rotating the tags

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Guirec · Answer 1 · 2012-09-30T22:49:00

Solution 1

Looks like the answer is somehow already in your question.

Create a class which holds a Timer which delegates every 5 minutes.
When the timer delegates then read your file, split the content, re-order the content and save back your file.

Posted 30-Sep-12 22:49pm

Guirec

Unareshraju · Answer 2 · 2012-09-30T22:53:00

Hi Shashwath,
Very strong to me,But try like this
Based on timer control we can iterate the XML file tags that should be consist of same root tag.

http://www.c-sharpcorner.com/UploadFile/mahesh/ReadWriteXMLTutMellli2111282005041517AM/ReadWriteXMLTutMellli21.aspx[^]

from above url while writing the XML Document Tags, we will keep the timer to iterate the
Nodes.