How do I conver this javascript arrow function into a normal function ?

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JavaScript

let items=[];

fetch("https://www.googleapis.com/books/v1/volumes?q=isbn:0747532699")
    .then(res => res.json())
    .then((result) => {
          items= result.items;
          console.log(items);
        }),
        (error) => {
            console.log(error);
           } ;

What I have tried:

let items=[];

fetch("https://www.googleapis.com/books/v1/volumes?q=isbn:0747532699")
    .then(res => res.json())
    .then((result) => {
          items= result.items;
          console.log(items);
        }),
        (error) => {
            console.log(error);
           } ;

JavaScript

Posted 22-Jun-20 1:03am

Cyborg girl

Updated 22-Jun-20 3:00am

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Maciej Los 22-Jun-20 7:40am

What you mean by "normal function"?

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jsc42 · Answer 1 · 2020-06-22T03:01:00

This is really only a useful exercise if you are converting down to ES3 e.g. for a Windows Hypertext Application. It is better to become familiar with the arrow syntax. However, if you must do it, this is how ...

1) Put the word 'function' before the parameter list,
2) If the parameter list is not in parentheses, surround the list in parentheses,
3) If the expression part after the arrow is not already enclosed in braces, enclose the expression in braces
4) Discard the arrow
5) If the expression returns a value, put 'return' in front of the final / only expression

e.g. res => res.json()
1) function res => res.json()
2) function (res) => res.json();
3) function (res) => { res.json(); }
4) function (res) { res.json(); }
5) function (res) { return res.jsoc(); }

or (result) => { items = result.items; console.log(items); }
1) function (result) => { items = result.items; console.log(items); }
2) /* not needed - parentheses already there */
3) /* not needed - braces already there */
4) function (result) { items = result.items; console.log(items); }
5) function (result) { items = result.items; return console.log(items); } // 'return' not really needed with console.log