Is that any problem when we use memset in below manner?

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hi,
char str[20];
memset(&str, 0, sizeof(str));

any issue will cross over it.
because for char array memset(&str, '\0', strlen(str)); literally lot of people use it.
so that am asking ?...please clarify it...

What I have tried:

i described my issue and my checking any segmentation issue will come in or not

Posted 6-Oct-21 19:42pm

maathesh

Updated 6-Oct-21 20:42pm

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CPallini · Answer 1 · 2021-10-06T20:16:00

Solution 1

No problem at all.
Yours is the correct way.

Posted 6-Oct-21 20:16pm

CPallini

KarstenK · Answer 2 · 2021-10-06T20:42:00

Solution 2

No, it correct. In more complex scenarios you must use the byte size of that memory block.

A nice shorthand is

C++

char str[20] = {0};

which enforces such a memset without further code.

Posted 6-Oct-21 20:42pm

KarstenK

Comments

CPallini 7-Oct-21 2:49am

5.