How do I transform a floating number into it's negative in C?

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I'm new to C, and I challanged myself to make an angle calculator in function of Vo, G, target X and target Y, yet I'm struggling with the simplest part of it, to convert a floating number into it's negative. I made a separate project in code blocks and have summarized my problem into a simpler code, take a look:

What I have tried:

C

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
    float V,Vi;
    char v;
    if(v=='-'){
        V=0-Vi;
    }else{
    V=Vi;
    }
        printf("Projectile initial velocity is + or -?\n");
        scanf(" %c", &v);
    printf("Projectile initial velocity module?\n");
        scanf("%lf", &Vi);
        printf("%f", V);
    return 0;
}

//This has an output of 1.875000 (??)

Posted 17-Jun-22 13:27pm

Member 15677885

Updated 19-Jun-22 13:22pm

Dave Kreskowiak

v2

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4 solutions

Solution 2

Quote:
I'm struggling with the simplest part of it, to convert a floating number into it's negative.

You mean make a positive float number negative?

C

float V, Vi;

V = 1;
Vi = -V;

Posted 17-Jun-22 14:07pm

merano99

Solution 3

Your coded logic is absolutely wrong. If you step through your code in debugger you will quickly figure this out

Posted 17-Jun-22 20:55pm

steveb

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k5054 · Accepted Answer · 2022-06-17T13:59:00

Generally speaking, for any language, multiplying by -1.0 changes the sign of a number, either integer or floating point.

I'm going to guess that something went wrong when you posted your code, since what you have here does some calculations with uninitialized data, prompts for values, then exits, which is guaranteed to give unexpected results. I also notice

C

float Vi;
scanf("%lf", &Vi);

The format specifier %lf tells scanf() to expect a pointer to a double (i.e. long float), but in this case Vi is a float. So again, its unknown what value Vi will ultimately get. It might be the value expect, it might be zero, or it might be some other, seemingly random value. Depending on the compiler you're using, turning on compiler warnings should catch that mistake.

Member 15677885 · Accepted Answer · 2022-06-19T13:22:00

Ok, so i had a brak and came back, after reading some solutions I've came um with this:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    float V,Vi;
    char opV;

    scanf(" %c", &opV);
    scanf("%fl", &Vi);
        if(opV=='-'){
        V = 0 - Vi ;
    }else{V=Vi;};
    printf("%f\n", V);
    return 0;
}

How do I transform a floating number into it's negative in C?

4 solutions

Solution 1

Solution 2

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