Write a program were the program can tell if the input entered is even or odd?

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Hi i need some help
Whats the best method for this question:

Write a program to check whether a number input by the user is even or odd?

Here is what i have done so far (Not Much)

C#

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace AS15_Number_4
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.Write("Please Enter Me A Number : ");
            string str = Console.ReadLine();
            int num1 = Convert.ToInt16(str);


        }
    }
}

Please Help ASAP Thank You.

Posted 4-Apr-13 23:21pm

Matthias Attard

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Comments

Pheonyx 5-Apr-13 5:25am

This sounds very much like homework. And from your namespace it looks like homework!
We are not here to do it for you.

I will ask you a simple question: forgetting computer code, how can you test if a number is odd or even?

3 solutions

Solution 2

Hi,

Though I am providing you with the solution.Please google for such simple stuff.

C#

using System;

using System.Collections.Generic;

using System.Text;



namespace OddEven

{

   class OddOREven

   {

      static bool ReadInteger(out int n)

      {

         string input = System.Console.ReadLine();

         n = 0;

         try

         {

            n = Convert.ToInt32(input);

            return true;

         }

         catch (System.Exception ex)

         {

            System.Console.WriteLine("Error in the input format\n\n");

            return false;

         }

      }

      static void Main(string[] args)

      {

         System.Console.Write("Enter a Number to Check ODD or EVEN: ");

         int number = 0;

         ReadInteger(out number);



         if((number % 2) == 0)

            System.Console.WriteLine("{0} is an EVEN number", number);

         else

            System.Console.WriteLine("{0} is an ODD number", number);

      }

   }

}

Posted 4-Apr-13 23:27pm

Prathap Gangireddy

Solution 3

You can check if a number is even by:

C#

bool isEven = (number % 2) == 0

or for odd:

C#

bool isOdd = (number % 2) == 1

and for zero:

C#

bool isZero = (number == 0);

you can also combine that to:

C#

var result = number==0 ? "zero" : number%2 == 0 ? "even" : "odd";
Console.WriteLine(result);

(if you don't know "?:" --> Ternary Operation[^])

Posted 4-Apr-13 23:28pm

Nicholas Marty

Comments

Thomas Daniels 5-Apr-13 5:44am

Zero is an even number:
http://en.wikipedia.org/wiki/Parity_of_zero

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Thomas Daniels · Accepted Answer · 2013-04-04T23:25:00

Solution 1

Hi,

Use the modulo operator %[^]:

C#

if ((num1 % 2) == 0)
{
    Console.WriteLine("even");
}
else
{
    Console.WriteLine("odd");
}

Hope this helps.

Posted 4-Apr-13 23:25pm

Thomas Daniels

Updated 4-Apr-13 23:33pm

v2