what is the out put for this program

Question

1.00/5 (4 votes)

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C++

#include<stdio.h>
main()
{
int i=2;
printf("%d %d %d %d %d"i,i++,++i,i--,--i);
}

please explain output

Posted 29-Aug-13 23:44pm

sairamchopparapu

Updated 29-Aug-13 23:48pm

User 59241

v2

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[no name] 30-Aug-13 5:50am

Why don't you run it and find out for yourself?

Nelek 30-Aug-13 5:59am

The easiest way is to compile and to run it, don't you think?

sairamchopparapu 30-Aug-13 6:02am

i got answer but i don't know its explanation....

Nelek 30-Aug-13 6:15am

Take a look to the links below

Richard MacCutchan 30-Aug-13 6:31am

Whatever you do it will probably be wrong. It is extremely bad practice to use code like that.

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Nelek · Accepted Answer · 2013-08-30T00:14:00

Solution 1

Have a look:
http://www.c4learn.com/increment-operator-in-c-programming.html[^]
http://www.learncpp.com/cpp-tutorial/33-incrementdecrement-operators-and-side-effects/[^]
http://www.tutorialspoint.com/cplusplus/cpp_increment_decrement_operators.htm[^]

http://stackoverflow.com/questions/24853/what-is-the-difference-between-i-and-i[^]
http://stackoverflow.com/questions/484462/difference-between-i-and-i-in-a-loop[^]

Posted 30-Aug-13 0:14am

Nelek

Comments

Prasad Khandekar 30-Aug-13 6:27am

5+

Nelek 30-Aug-13 6:28am

Thank you

sairamchopparapu 30-Aug-13 6:41am

so thanks

Nelek 30-Aug-13 6:44am

You are welcome

cyber_addicted · Accepted Answer · 2013-08-30T00:27:00

Solution 2

actually compiler go from right to left so right most expression is --i; it means it first change value of i from 2 to 1 and print 1 then i-- it means first print value of i i.e. 1 and then decrease the value of i to 0 then ++i first increases the value of i to 1 then print 1 and next one is i++ it first print value of i i.e. 1 and the increase the value and at last value of i is 2 so it print it 2 and print order is left to right so it prints 2 1 1 1 1.

Posted 30-Aug-13 0:27am

cyber_addicted

v2

Comments

sairamchopparapu 30-Aug-13 6:40am

but in fedora os out put shows 2 1 2 1 2......how is it possible

[no name] 30-Aug-13 6:48am

its depend on compiler to compiler i am describing the output of turbo c on win32. in c compiler output depends on platform and compiler so that's why u getting different output.

sairamchopparapu 30-Aug-13 6:52am

ok so thanks for explanation..