dynamically added column in gridview at right most place

Question

0.00/5 (No votes)

See more:

this is my asp

XML

<body>
    <form id="form1" runat="server">
    <div>
        <asp:GridView ID="GridView1" runat="server"
            onrowdatabound="GridView1_RowDataBound" DataKeyNames="head_code" >
        </asp:GridView>

    </div>
    </form>
</body>

This is my code.

C#

protected void Page_Load(object sender, EventArgs e)
   {
       hitechLatestEntities database = new hitechLatestEntities();
       GridView1.DataSource = database.HEADs;

       TemplateField tfObject = new TemplateField();
       tfObject.HeaderText = "Sub-Heads Details";

       tfObject.ItemTemplate = new WebForm1(ListItemType.Item);
       GridView1.Columns.Add(tfObject);
      GridView1.DataBind();
   }

I want this recently added column at right most place of the gridview1. For now it is appearing at left most.

Posted 29-Jan-14 1:15am

Basit Elahi

Updated 29-Jan-14 2:08am

Tom Marvolo Riddle

v3

Add a Solution

Comments

Karthik_Mahalingam 29-Jan-14 7:23am

post your gridview code. aspx

Basit Elahi 29-Jan-14 7:38am

<asp:GridView ID="GridView1" runat="server"
onrowdatabound="GridView1_RowDataBound" DataKeyNames="head_code" >

I am doing most of the work programatically

Karthik_Mahalingam 29-Jan-14 7:58am

post full gridview code..

Basit Elahi 29-Jan-14 8:05am

i have updated the question. please check it

Karthik_Mahalingam 29-Jan-14 8:07am

so everything you are adding in code behind only ??
how many columns ??

Basit Elahi 29-Jan-14 8:10am

for now it has two columns. yes i am doing it from code behind

Karthik_Mahalingam 29-Jan-14 8:12am

post your full cs code for creating dynamic columns...

Basit Elahi 29-Jan-14 8:13am

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;

namespace nested_gridview_from_vb
{
public partial class WebForm1 : System.Web.UI.Page , ITemplate
{
protected void Page_Load(object sender, EventArgs e)
{
hitechLatestEntities database = new hitechLatestEntities();
GridView1.DataSource = database.HEADs;

TemplateField tfObject = new TemplateField();
tfObject.HeaderText = "Sub-Heads Details";

tfObject.ItemTemplate = new WebForm1(ListItemType.Item);
GridView1.Columns.Insert(0,tfObject);
GridView1.DataBind();

}

protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{

string headCode = GridView1.DataKeys[e.Row.RowIndex].Value.ToString();

hitechLatestEntities data = new hitechLatestEntities();
var result = from t in data.SUB_HEAD
join x in data.HEADs on t.head_code equals x.head_code
where t.head_code == headCode
select new { t.sub_head_code,t.particulars };

GridView sub = e.Row.FindControl("newg") as GridView;
sub.DataSource = result;
sub.DataBind();

}
}

public WebForm1()
{
}

public WebForm1(ListItemType Item)
{
myListItemType = Item;
}
private ListItemType myListItemType;
public void InstantiateIn(Control container)
{

if (myListItemType == ListItemType.Item)
{
hitechLatestEntities data = new hitechLatestEntities();
GridView newgrid = new GridView();

newgrid.ID = "newg";
newgrid.DataSource = data.SUB_HEAD;
newgrid.DataBind();
container.Controls.Add(newgrid);
}
}
}

Karthik_Mahalingam 29-Jan-14 8:18am

by any chance , is this working ?

Basit Elahi 29-Jan-14 8:23am

yes it is working fine

Karthik_Mahalingam 29-Jan-14 8:29am

this wil print in left most only...
GridView1.Columns.Insert(0,field);

JoCodes 29-Jan-14 10:29am

Tried the same with AutoGenerateColumn to false?

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

ravikhoda · Answer 1 · 2014-01-29T01:32:00

Solution 1

please try and set gridview.column.display index

Hi, sorry for my answer. display index is i think used in window applicatio not web application.

in web site you can chek below link .

http://stackoverflow.com/questions/8976153/how-to-reorder-columns-in-gridview-dynamically

Posted 29-Jan-14 1:32am

ravikhoda

Updated 29-Jan-14 2:02am

v2

Comments

Basit Elahi 29-Jan-14 7:50am

can u give me some example ravikhoda??

Karthik_Mahalingam · Answer 2 · 2014-01-29T02:32:00

try like this..

C#

DataControlFieldCollection allcolumns =  GridView1.Columns;
         GridView1.Columns.Clear();
         GridView1.Columns.Add(allcolumns[0]);  // you can change the index in which order u need to display
         GridView1.Columns.Add(allcolumns[1]);
         GridView1.Columns.Add(allcolumns[2]);
         GridView1.Columns.Add(allcolumns[3]);
         GridView1.DataBind();